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Dennis_Churaev [7]
3 years ago
11

You might have noticed that a feather falls slowly toward the ground, while a ball falls rapidly. Which statement correctly expl

ains the motion of these objects?
1. The ball does not experience fluid friction as it falls.
2. Gravity is the only force acting on the feather and the ball.
3.The acceleration of the ball and feather are the same.
4. The feather experiences more fluid friction than the ball.
Physics
1 answer:
Brut [27]3 years ago
3 0

Answer:

4. the feather experiences more fluid friction than the ball

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Air at 25°C and 5 atm is throttled by a valve to 1 atm. If the valve is adiabatic and the change in kinetic energy is negligible
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Answer:

T_{2} = 25^{\circ}C

Solution:

As per the question:

Temperature, T_{1} = 25^{\circ}C

Pressure, P_{1} = 5 atm[\tex]Now,We know that the process of throttling occurs in adiabatic conditions where no heat is transferred in between the system and the surrounding, i.e., Q = 0Thus no work is done in this process, i.e., W = 0Enthalpy also remains same from one state to the other state, i.e., [tex]\Delta h = 0

Therefore, from the eqn:

Q - W = \Delta h + \Delta KE

We can write:

\Delta h = h_{1} - h_{2} = 0

\Delta h = C_{p}\Delta T

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4 0
3 years ago
A) At a certain instant, a particle-like object is acted on by a force F = (3.0 N) ihat - (3.0 N) jhat + (9.0 N) khat while the
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Answer:

a) Instantaneous rate at which the force does work on the object = -6 W

b) \texttt{Velocity of object,}\vec{v}=4\hat{j}

Explanation:

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   and

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Instantaneous rate at which the force does work on the object is called power.

          Power is the dot product of force and velocity.

          P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).(-2\hat{i}+4\hat{k})=-6W

Instantaneous rate at which the force does work on the object = -6 W

b) Here given that    \vec{v}=-a\hat{j}

  Power = -12 W

  P=\vec{F}.\vec{v}=(3\hat{i}-3\hat{j}).a\hat{j}=-12W\\\\-3a=-12\\\\a=4\\\\\vec{v}=4\hat{j}

\texttt{Velocity of object,}\vec{v}=4\hat{j}

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2 years ago
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ANSWER

3.30\text{ m/s}

EXPLANATION

Parameters given:

Mass of car, mc = 1103 kg

Mass of truck, mt = 4919 kg

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Inital velocity of truck = 0 m/s

To solve this problem, we have to apply the law of conservation of momentum, which states that the total momentum of a system is constant.

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