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3 years ago

Write one example situation of Newton's Third Law involving mass that are the same.

Physics

1 answer:

puteri [66]3 years ago

6 0

Answer:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

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Raindrops acquire an electric charge as they fall. Suppose a 2.4-mm-diameter drop has a charge of +18 pC, fairly typical values.

muminat

To solve this problem we will apply the concepts related to the potential, defined from the Coulomb laws for which it is defined as the product between the Coulomb constant and the load, over the distance that separates the two objects. Mathematically this is

$V = \frac{kq}{r}$

k = Coulomb's constant

q = Charge

r = Distance between them

$q = 18 pC \rightarrow q = 1.8*10^-11 C$

$d = 2.4mm \rightarrow r = 1.2 mm = 1.2*10^-3 m$

Replacing,

$V = \frac{kq}{r}$

$V = \frac{ (9*10^9)*(1.8*10^{-11})}{(1.2*10^{-3})}$

$V = 135 V$

Therefore the potential at the surface of the raindrop is 135 V

3 0

2 years ago

How long does it take an airplane to fly 1200 miles if it maintains a speed of 300 miles per hour

sdas [7]

Answer:

The answer is

Explanation:

To find the time taken we use the formula

$t = \frac{d}{v} \\$

where

d is the distance covered

v is the velocity

t is the time

From the question

d = 1200 miles

v = 300 mi/hr

We have

$t = \frac{1200}{300} = \frac{12}{3} \\$

We have the final answer as

Hope this helps you

5 0

2 years ago

The graph above shows the position and time calculate the velocity of the particle from T=0s to T=4s?

zzz [600]

Answer:

The velocity of the particle from T = 0 s to T = 4 s is;

0.5 m/s

Explanation:

The given parameters from the graph are;

The initial displacement (covered) at time, t₁ = 0 s is x₁ = 1 m

The displacement covered at time, t₂ = 4 s is x₂ = 3 m

The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;

$The \ slope \ of \ the \ displacement \ time \ graph, \ m =velocity, \ v= \dfrac{x_2 - x_1}{t_2 - t_1}$

$Therefore, \ the \ velocity \ of \ the \ particle \ v = \dfrac{3 \ m - 1 \ m}{4 \ s - 0 \ s} = \dfrac{2 \ m}{4 \ s} = \dfrac{1}{2} \ m/s$

The velocity of the particle from t = 0 s to t = 4 s = 1/2 m/s = 0.5 m/s.

3 0

2 years ago

A kicker kicks a ball off the ground at 29.5 mi/hr and at 42.5 degrees. How far did this kick travel?

hram777 [196]

Answer:

88.5miles

Explanation:

the formula used to get the horizontal distance is R= (u^2sin2∆)÷g.

4 0

3 years ago

According to your graph, does the wave speed change with wave length?

fiasKO [112]

Yes

Explanation:

From the graph, we can deduce that the wavelength changes with the speed of the wave.

This is a simple linear graph. A linear graph has a steady gradient and it shows two variables that increases proportionately.

Using the graph, we can establish that as the wavelength of the wave increases the time taken for one wave to pass through increases.

The speed of a wave is given as:

V = fλ

f is the frequency of the wave i.e the number of waves that passes through a point per unit of time

λ is the wavelength of the wave

The vertical axis on the graph shows the time for 1 wave trip, this is the wave period, T

f = $\frac{1}{T}$

Therefore;

speed of the wave = $\frac{λ}{T}$

This can be evaluated by solving slope of the graph and finding the inverse.

We can see that as the speed of the wave changes, the wavelength will change.

learn more:

Wavelength brainly.com/question/6352445

#learnwithBrainly

3 0

2 years ago