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givi [52]
4 years ago
13

Jump starting a car requires

Engineering
1 answer:
Paha777 [63]4 years ago
3 0

Answer:

To safely jump a start, follow these steps:

Take out your jumper cables. ...

Place both vehicles in Park or Neutral and shut off the ignition in both cars. ...

Attach one of the red clips to the positive terminal of your battery. ...

Attach the other red clip to the positive terminal of the other car.

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How does the resistance in the circuit impact the height and width of the resonance curve? (If the resistance were to increase w
amm1812

Answer:

The reactances vary with frequency, with large XL at high frequencies and large Xc at low frequencies, as we have seen in three previous examples. At some intermediate frequency fo, the reactances will be the same and will cancel, giving Z = R; this is a minimum value for impedance and a maximum value for Irms results. We can get an expression for fo by taking

XL=Xc

Substituting the definitions of XL and XC,

2\pifoL=1/2\pifoC

Solving this expression for fo yields

fo=1/2\pi\sqrt{LC}

where fo is the resonant frequency of an RLC series circuit. This is also the natural frequency at which the circuit would oscillate if it were not driven by the voltage source. In fo, the effects of the inductor and capacitor are canceled, so that Z = R and Irms is a maximum.

Explanation:

Resonance in AC circuits is analogous to mechanical resonance, where resonance is defined as a forced oscillation, in this case, forced by the voltage source, at the natural frequency of the system. The receiver on a radio is an RLC circuit that oscillates best at its {f} 0. A variable capacitor is often used to adjust fo to receive a desired frequency and reject others is a graph of current versus frequency, illustrating a resonant peak at Irms at fo. The two arcs are for two dissimilar circuits, which vary only in the amount of resistance in them. The peak is lower and wider for the highest resistance circuit. Thus, the circuit of higher resistance does not resonate as strongly and would not be as selective in a radio receiver, for example.

A current versus frequency graph for two RLC series circuits that differ only in the amount of resistance. Both have resonance at fo, but for the highest resistance it is lower and wider. The conductive AC voltage source has a fixed amplitude Vo.

4 0
3 years ago
what do you think the author is trying to express to society during his time of period through this story? in the open window
jekas [21]
Vroom vroom move uno rass
3 0
4 years ago
You are preparing to work with Chemical A. You open the appropriate storage cabinet, and notice Chemical B, as well as Chemical
PtichkaEL [24]

The correct answer is; Stability and reactivity.

Further Explanation:

The stability and reactivity section of the SDS sheets is where to check for the possibility of hazardous reactions for the chemicals. This also lists the chemical stability of each chemical that people may be using. This can be found in section 10 of the OSHA Quick Card.

The SDS sheets has 16 sections for employees to use. Since 2015, the sections can be found in uniform format for easier and faster ways to find the section needed. The 16 sections for the SDS sheets are:

  1. Identification
  2. Hazard(s) identification
  3. Composition/information on ingredients
  4. First-aid measures
  5. First-aid measures
  6. First-aid measures
  7. Handling and storage
  8. Exposure controls/personal protection
  9. Physical and chemical properties
  10. Stability and reactivity
  11. Toxicological information
  12. Ecological information
  13. Disposal considerations
  14. Transport information
  15. Regulatory information
  16. Other information

Learn more about SDS sheets at brainly.com/question/9753408

#LearnwithBrainly

5 0
4 years ago
Mechanical clips are used to close bags and keep things together. Investigate the design of various paper clips, hair clips, and
pochemuha

Answer:

Hair clip: this used to hold human hairs together especially long hairs

The Design parameters to be considered are : number of teeth, durability of the material to be used and also the width ( how wide the clip can open )

Advantages : very easy to use, holds hairs tight

Disadvantages : Expensive and material used is sometimes brittle

paper clips : This used to hold papers together it is made of a thin elastic wire

The design parameters to be considered are : length of the wire, material to be used and the elasticity of the material

advantages : it is quite cheap and good strength

disadvantages :it can hold a limited amount of papers together

potato chip bag clips: These clips are used on potato chip bags to ensure that the bags are air tight

The design parameters to be considered are : Elasticity of the material to be used , and size

Advantages : it helps to prevent the potato chips from getting exposed to air

disadvantages : Not very popular and its quite expensive

Explanation:

Hair clip: this used to hold human hairs together especially long hairs

The Design parameters to be considered are : number of teeth, durability of the material to be used and also the width ( how wide the clip can open )

Advantages : very easy to use, holds hairs tight

Disadvantages : Expensive and material used is sometimes brittle

paper clips : This used to hold papers together it is made of a thin elastic wire

The design parameters to be considered are : length of the wire, material to be used and the elasticity of the material

advantages : it is quite cheap and good strength

disadvantages :it can hold a limited amount of papers together

potato chip bag clips: These clips are used on potato chip bags to ensure that the bags are air tight

The design parameters to be considered are : Elasticity of the material to be used , and size

Advantages : it helps to prevent the potato chips from getting exposed to air

disadvantages : Not very popular and its quite expensive

4 0
3 years ago
The 30-kg gear is subjected to a force of P=(20t)N where t is in seconds. Determine the angular velocity of the gear at t=4s sta
tatyana61 [14]

Answer:

\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}

Explanation:

Previous concepts

Angular momentum. If we consider a particle of mass m, with velocity v, moving under the influence of a force F. The angular  momentum about point O is defined as the “moment” of the particle’s linear momentum, L, about O. And the correct formula is:

H_o =r x mv=rxL

Applying Newton’s second law to the right hand side of the above equation, we have that r ×ma = r ×F =

MO, where MO is the moment of the force F about point O. The equation expressing the rate of change  of angular momentum is this one:

MO = H˙ O

Principle of Angular Impulse and Momentum

The equation MO = H˙ O gives us the instantaneous relation between the moment and the time rate of change of angular  momentum. Imagine now that the force considered acts on a particle between time t1 and time t2. The equation MO = H˙ O can then be integrated in time to obtain this:

\int_{t_1}^{t_2}M_O dt = \int_{t_1}^{t_2}H_O dt=H_0t2 -H_0t1

Solution to the problem

For this case we can use the principle of angular impulse and momentum that states "The mass moment of inertia of a gear about its mass center is I_o =mK^2_o =30kg(0.125m)^2 =0.46875 kgm^2".

If we analyze the staritning point we see that the initial velocity can be founded like this:

v_o =\omega r_{OIC}=\omega (0.15m)

And if we look the figure attached we can use the point A as a reference to calculate the angular impulse and momentum equation, like this:

H_Ai +\sum \int_{t_i}^{t_f} M_A dt =H_Af

0+\sum \int_{0}^{4} 20t (0.15m) dt =0.46875 \omega + 30kg[\omega(0.15m)](0.15m)

And if we integrate the left part and we simplify the right part we have

1.5(4^2)-1.5(0^2) = 0.46875\omega +0.675\omega=1.14375\omega

And if we solve for \omega we got:

\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}

8 0
3 years ago
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