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3 years ago

Jump starting a car requires

Engineering

1 answer:

Paha777 [63]3 years ago

3 0

Answer:

To safely jump a start, follow these steps:

Take out your jumper cables. ...

Place both vehicles in Park or Neutral and shut off the ignition in both cars. ...

Attach one of the red clips to the positive terminal of your battery. ...

Attach the other red clip to the positive terminal of the other car.

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Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter.

Explanation:

Mass is the matter that makes up objects

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3 years ago

Does anybody know what plane this is? i saw it the other day doing a low pass through my community

Arlecino [84]

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Airbus A340-313

Explanation:

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2 years ago

List in order first three steps to square a board

LenaWriter [7]

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3 years ago

Which side of the disc sander do you sand on <br> 1. Right <br> 2. Left<br> 3. Up<br> 4. Down

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2 years ago

Steam enters a turbine operating at steady state with a mass flow of 10 kg/min, a specific enthalpy of 3100 kJ/kg, and a velocit

Natali [406]

Answer:

$\dot W_{out} = 133.327\,kW$

Explanation:

The model for the turbine can be derived by means of the First Law of Thermodynamics:

$-\dot Q_{out}-\dot W_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right] =0$

The work produced by the turbine is:

$\dot W_{out}=-\dot Q_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right]$

The mass flow and heat transfer rates are, respectively:

$\dot m = (10\frac{kg}{min})\cdot (\frac{1\,min}{60\,s} )$

$\dot m = 0.167\,\frac{kg}{s}$

$\dot Q_{out} = (0.167\,\frac{kg}{s} )\cdot (1.1\times 10^{3}\,\frac{J}{kg} )$

$\dot Q_{out} = 183.7\,W$

Finally:

$\dot W_{out} = -183.7\,W + (0.167\,\frac{kg}{s} )\cdot \left(8\times 10^{5}\,\frac{J}{kg} -562,5\,\frac{J}{kg} +29.43\,\frac{J}{kg} \right)$

$\dot W_{out} = 133.327\,kW$

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3 years ago