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givi [52]
3 years ago
13

Jump starting a car requires

Engineering
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

To safely jump a start, follow these steps:

Take out your jumper cables. ...

Place both vehicles in Park or Neutral and shut off the ignition in both cars. ...

Attach one of the red clips to the positive terminal of your battery. ...

Attach the other red clip to the positive terminal of the other car.

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katen-ka-za [31]

Answer:

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Explanation:

7 0
3 years ago
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Suppose you are implementing a relational employee database, where the database is a list of tuples formed by the names, the pho
m_a_m_a [10]

Answer:

Explanation:

val db = ("John", "x3456", 50.1) :: ("Jane", "x1234", 107.3) ::

        ("Joan", "unlisted", 12.7) :: Nil

 

type listOfTuples = List[(String, String, Double)]

def find_salary(name: String) = {

 def search(t: listOfTuples): Double = t match {

   case (name_, _, salary) :: t if name == name_ => salary

   case _ :: t => search(t)

   case Nil    =>

     throw new Exception("Invalid Argument in find_salary")

 }

 search(db)

}

def select(pred: (String, String, Double) => Boolean) = {

 def search(found: listOfTuples): listOfTuples = found match {

   case (p1, p2, p3) :: t if pred(p1, p2, p3)  => (p1, p2, p3) :: search(t)

   case (p1, p2, p3) :: t if !pred(p1, p2, p3) => search(t)

   case Nil => Nil

   case _ => throw new Exception("Invalid Argument in select function")

 }

 search(db)

}

 

println("Searching the salary of 'Joan' at db: " + find_salary("Joan"))

println("")

 

val predicate = (_:String, _:String, salary:Double) => (salary < 100.0)

println("All employees that match with predicate 'salary < 100.0': ")

println("\t" + select(predicate) + "\n")

7 0
3 years ago
The following two DC motors are to be compared for certain application:
7nadin3 [17]
Explain simply pleaseeeeeee
3 0
3 years ago
Water is pumped from one large reservoir to another at a higher elevation. If the flow rate is 2.5 ft3 /s and the pump delivers
4vir4ik [10]

Answer:

2132hp  ed enregia

e

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6 0
3 years ago
A steam power plant with a power output of 230 MW consumes coal at a rate of 60 tons/h. If the heating value of the coal is 30,0
NARA [144]

Answer:

\eta =46\%

Explanation:

Hello!

In this case, we compute the heat output from coal, given its heating value and the mass flow:

Q_H=60\frac{tons}{h}*\frac{1000kg}{1ton}*\frac{1h}{3600s}*\frac{30,000kJ}{kg}\\\\Q_H=500,000\frac{kJ}{s}*\frac{1MJ}{1000J} =500MW

Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:

\eta =\frac{230MW}{500MW}*100\% \\\\\eta =46\%

Best regards!

7 0
3 years ago
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