Which Two moon phases are directly opposite each other?
2 answers:
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The composition of gas in the feed, the percentage conversion and the
theoretical yield are combined to give the product stream composition.
Response:
The composition of gas in the product stream are;
- HCl: 0.4 kmol/h, Cl₂: 1.6 kmol/h, H₂O: 1.6 kmol/h, O₂: 0.5 kmol/h
The amount of oxygen used = 30% exceeding the theoretical amount
Number of moles of hydrochloric acid = 4 kmol/h
Percentage conversion = 80%
Required:
The composition of the gas in the product feed.
Solution;
The given reaction is; 4HCl + O₂ 2Cl₂ + 2H₂O
Which gives;
Moles of limiting reactant reacted = 4 kmol/h × 0.80 = 3.6 kmol/h
Which gives;
Number of moles of HCl in the stream = 4 kmol/h - 3.6 kmol/h = 0.4 kmol/h
Number of moles of Cl₂ produced = 2 kmol/h × 0.8 = 1.6 kmol/h
Similarly;
Number of moles of H₂O produced = 2 kmol/h × 0.8 = 1.6 kmol/h
Number of moles of O₂ in the product stream = 30% × 1 kmol/h + 20% × 1 kmol/h = 0.5 kmol/h
The composition of the production stream is therefore;
- <u>HCl: 0.4 kmol/h</u>
- <u>Cl₂: 1.6 kmol/h</u>
- <u>H₂O: 1.6 kmol/h</u>
- <u>O₂: 0.5 kmol/h</u>
Learn more about theoretical and actual yield here:
Answer:
volume of biological sludge = 28.566 m³ per day
Explanation:
given data
mass of solid = 7240 kg/day
initial moisture content = 78%
solution
here percentage of solid will be
% of solid = 100 - initial moisture content
% of solid = 100 - 78 = 22 %
so that
mass of sludge produced = kg per day
put her value
mass of sludge produced = kg
mass of sludge produced = 32909.09 kg
so
specific gravity of sludge =
and as we know that
= 1.152
so that
density of sludge = S sludge × density of water
density of sludge = 1.152 × 1000
density of sludge = 1152 kg/m³
so that
volume of biological sludge =
volume of biological sludge =
volume of biological sludge = 28.566 m³ per day