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sergiy2304 [10]
3 years ago
8

What are the 3 components of a rocket?

Chemistry
1 answer:
sleet_krkn [62]3 years ago
6 0
Rocket Parts

The study of rockets is an excellent way for students to learn the basics of forces and the response of an object to external forces. In flight, a rocket is subjected to the forces of weight, thrust, and aerodynamics. On this slide, we have removed the outer "skin" so that we can see the parts that make a rocket. There are many parts that make up a rocket. For design and analysis, engineers group parts which have the same function into systems. There are four major systems in a full scale rocket; thestructural system, the payload system, the guidance system, and the propulsion system.

The structural system, or frame, is similar to the fuselage of an airplane. The frame is made from very strong but light weight materials, like titanium or aluminum, and usually employs long "stringers" which run from the top to the bottom which are connected to "hoops" which run around around the circumference. The "skin" is then attached to the stringers and hoops to form the basic shape of the rocket. The skin may be coated with a thermal protection system to keep out the heat of air friction during flight and to keep in the cold temperatures needed for certain fuels and oxidizers. Fins are attached to some rockets at the bottom of the frame to provide stability during the flight.

The payload system of a rocket depends on the rocket's mission. The earliest payloads on rockets were fireworks for celebrating holidays. The payload of the German V2, shown in the figure, was several thousand pounds of explosives. Following World War II, many countries developed guided ballistic missiles armed with nuclear warheads for payloads. The same rockets were modified to launch satellites with a wide range of missions; communications, weather monitoring, spying, planetary exploration, and observatories, like the Hubble Space Telescope. Special rockets were developed to launch people into earth orbit and onto the surface of the Moon.

The guidance system of a rocket may include very sophisticated sensors, on-board computers, radars, and communication equipment to maneuver the rocket in flight. Many different methods have been developed to control rockets in flight. The V2 guidance system included small vanes in the exhaust of the nozzle to deflect the thrust from the engine. Modern rockets typically rotate the nozzle to maneuver the rocket. The guidance system must also provide some level of stability so that the rocket does not tumble in flight.

As you can see on the figure, most of a full scale rocket is propulsion system. There are two main classes of propulsion systems, liquid rocket enginesand solid rocket engines. The V2 used a liquid rocket engine consisting of fuel and oxidizer (propellant) tanks, pumps, a combustion chamber with nozzle, and the associated plumbing. The Space Shuttle, Delta II, and Titan III all use solid rocket strap-ons.

The various rocket parts described above have been grouped by function into structure, payload, guidance, and propulsion systems. There are other possible groupings. For the purpose of weight determination and flight performance, engineers often group the payload, structure, propulsion structure (nozzle, pumps, tanks, etc.), and guidance into a single empty weight paramter. The remaining propellant weight then becomes the only factor that changes with time when determining rocket performance.

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Three Balanced equations for Ammonium salt+Alkali=Salt+water+carbon dioxide
arlik [135]

Answer:

NH₄Cl (aq) + NaOH (aq) -> NaCl (aq) + H₂O (l) + NH₃ (g)

(NH₄)₂CO₃ (aq) + 2KOH (aq) -> K₂CO₃ (aq) + 2H₂O (l) + 2NH₃(g)

NH₄NO₃ (aq) + LiOH (aq) -> LiNO₃ (aq) + H₂O (l) + NH₃ (g)

Explanation:

The gas liberated when an alkali reacts with an ammonium salt is NH₃ (ammonia), not CO₂.

4 0
3 years ago
What are the characteristics of non-ideal solutions? a. The solute-solute and solvent- solvent interaction is different fromm th
finlep [7]

Answer:All the above

Explanation:

Non-ideal solutions are those solutions which do not obey Raoult's law in any conditions.

The molecular interactions of two components that is solute and solvent  are different.

If there are two components A and B then the molecular interaction between A-A,B-B would be different from the molecular interactions in A-B .

The enthalpy of mixing and volume of mixing for non-ideal solutions have  non zero values.

Enthalpy of mixing can be negative or positive in case of non-ideal solutions. If the enthalpy of mixing is negative so energy has been  released upon mixing the two components and if enthalpy of mixing is positive then energy is absorbed upon mixing the two components.

Non-ideal solutions are simply those solutions which are not ideal hence they should not be having the characterstics of ideal solutions.

For ideal solutions the molecular interactions between  the two components are equal.

So the molecular interaction between A-A,B-B  would be equal to the molecular interaction between A-B. Also the enthalpy of mixing and volume of mixing for ideal solutions are zero hence all the statements provided here are correctly charactersing non-ideal solutions.

4 0
4 years ago
Help? please? can someone tell me how to do it​
kykrilka [37]

Answer:

8.82 x 10^-4 grams

Explanation:

We use the unit conversion method and the conversion using prefixes. Micro means 10^-6 grams, so multiplying it by 882 g results in the value shown in the answer

5 0
4 years ago
List the following elements in order of increasing number of valence electrons: C, CI, As, Na, He.
lorasvet [3.4K]
B is the correct answer
4 0
4 years ago
Sulfur dioxide and oxygen react to form sulfur trioxide, like this: (g) (g) (g) Also, a chemist finds that at a certain temperat
OLEGan [10]

Answer:

Kp=9.2x10^{-3}

Explanation:

Hello!

In this case, for the undergoing chemical reaction at equilibrium:

2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)

Which means that pressure-based equilibrium constant is computed via the following equilibrium expression:

Kp=\frac{p_{SO_3}^2}{p_{SO_2}^2p_{O_2}}

Thus, by plugging in the given pressures at equilibrium, the required Kp turns out:

Kp=\frac{55.0^2}{70.2^2*66.7}\\\\Kp=9.2x10^{-3}

Best regards!

3 0
3 years ago
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