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2 years ago

How many moles are in 68 grams of Mg(OH)

Chemistry

1 answer:

klemol [59]2 years ago

4 0

Answer:

1.16 mol

Explanation:

Given data:

Mass in gram Mg(OH)₂ = 68 g

Number of moles of Mg(OH)₂ = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of Mg(OH)₂ = 58.32 g/mol

By putting values,

Number of moles = 68 g/ 58.32 g/mol

Number of moles = 1.16 mol

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Which of the following is an anion?Al3+ Mg2+ O2– H Save

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3 years ago

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Answer:

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Explanation:

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3 years ago

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What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?

deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

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3 years ago

Based on your observations, which equation best models the reaction of vinegar (C2H4O2) and baking soda (NaHCO3)? Explain.

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3 years ago

Hydrogenation reactions, in which H2 and an "unsaturated" organic compound combine, are used in the food, fuel, and polymer indu

ddd [48]

<u>Answer:</u> The amount of heat released is 56 MJ.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of $C_2H_6$ = 12 kg = 12000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of $C_2H_6$ = 30 g/mol

Putting values in above equation, we get:

$\text{Moles of }C_2H_6=\frac{12000g}{30g/mol}=400mol$

The chemical reaction for hydrogenation of ethene follows the equation:

$C_2H_4+H_2\rightarrow C_2H_6$

By Stoichiometry of the reaction:

When 1 mole of ethane releases 140 kJ of heat.

So, 400 moles of ethane will release = $\frac{140}{1}\times 400=56000kJ$ of heat.

Converting this into Mega joules, using the conversion factor:

1 MJ = 1000 kJ

So, $\Rightarrow 56000kJ\times (\frac{1MJ}{1000kJ})=56MJ$

Hence, the amount of heat released is 56 MJ.

8 0

3 years ago