Answer:
B. N₂O₄.
Explanation:
- We will suppose the fuel has the formula NxOy.
- <em>The molar mass of the fuel = (x . atomic mass of N) + (y . atomic mass of O) = 92.0 g/mole.</em>
<em>The % composition of N = 30.43 %</em>
- The % composition of N = (x.atomic mass of N)/(molar mass of fuel) x 100.
- then x = (% composition of N)(molar mass of fuel) / 100(atomic mass of N) = (30.43 %)(92.0 g/mole) / 100(14.00 g/mole) = 1.9996 ≅ 2.0.
<em><u>By the same way; </u></em>
<em>The % composition of O = 69.57 %</em>
- The % composition of O = (y.atomic mass of O)/(molar mass of fuel) x 100
- then y = (% composition of O)(molar mass of fuel) / 100(atomic mass of O) = (69.57 %)(92.0 g/mole) / 100(16.00 g/mole) = 4.0.
<u><em>So, the formula of the compound is N₂O₄.</em></u>
Answer:
they are made from synthesized polymers of small molecules.
Explanation:
The compounds that are used to make these fibers come from raw materials such as petroleum based chemicals or petrochemicals. These materials are polymerized into a chemical that bonds two adjacent carbon atoms.