A rocket blasts off and moves straight upward from the launch pad with constant acceleration. after 3.6 s the rocket is at a hei
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Question is missing. Found on google:
a) What are the components of the acceleration of the fish?
(b) What is the direction of its acceleration with respect to unit vector î?
(c) If the fish maintains constant acceleration, where is it at t = 30.0 s?
(a)
The initial velocity of the fish is
while the final velocity is
Initial and final velocity are related by the following suvat equation:
where
a is the acceleration
t is the time
The time in this case is t = 15.0 s, so we can use the previous equation to find the acceleration, separating the components:
(b)
The direction of the acceleration vector with respect to i can be found by using the formula
where
is the horizontal component of the acceleration
is the vertical component of the acceleration
From part a), we have
Substituting,
(c)
The initial position of the fish is
The generic position r at time t is given by
where
is the initial velocity
is the acceleration
Substituting t = 30.0 s, we find the final position of the fish. Separating each component:
So the final position is