=
50MW is our net output.
Then, we plug it in.
= 
= 0.333 or 33.33%
W net, out = Qh - Ql
Ql = Qh - W net,out
Plug the values in.
Then, it becomes:
= 150MW - 50 MW
= 100MW
Thus, the cycle thermal efficiency is 33.33% and the heat rejected is 100MW.
Answer:
D. The inertia of a spaceship on Earth equals the inertia of the spaceship on the moon.
Explanation:
Inertia is the property of mass and it will directly depends on the value of mass of the object
So here inertia of object will change as the mass of the object will change
So here we can say
A. Inertia depends on velocity.
FALSE
As inertia is not a function of velocity
B. Inertia is a measurement of acceleration.
FALSE
it does not depends on acceleration
C. The inertia of a 2 kg bag of flour is greater than the inertia of a 4 kg flower pot.
FALSE
More mass means more inertia so 4 kg must have more inertia
D. The inertia of a spaceship on Earth equals the inertia of the spaceship on the moon.
TRUE
Since mass on Earth and Moon will be same so inertia must be same
A pair of scissors .....................................
Answer:
1) an observer in B 'sees the two simultaneous events
2)observer B sees that the events are not simultaneous
3) Δt = Δt₀ /√ (1 + v²/c²)
Explanation:
This is an exercise in simultaneity in special relativity. Let us remember that the speed of light is the same in all inertial systems
1) The events are at rest in the reference system S ', so as they advance at the speed of light which is constant, so it takes them the same time to arrive at the observation point B' which is at the point middle of the two events
Consequently an observer in B 'sees the two simultaneous events
2) For an observer B in system S that is fixed on the Earth, see that the event in A and B occur at the same instant, but the event in A must travel a smaller distance and the event in B must travel a greater distance since the system S 'moves with velocity + v. Therefore, since the velocity is constant, the event that travels the shortest distance is seen first.
Consequently observer B sees that the events are not simultaneous
3) let's calculate the times for each event
Δt = Δt₀ /√ (1 + v²/c²)
where t₀ is the time in the system S' which is at rest for the events
<span>The total amount of kinetic energy and potential energy within a system is called "Mechanical Energy"
In short, Your Answer would be Option C
Hope this helps!</span>
