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qwelly [4]
4 years ago
15

Enter the value for x that makes the equation true 36(x-5)=9x-18

Mathematics
1 answer:
s2008m [1.1K]4 years ago
3 0

Answer:

x = 6

Step-by-step explanation:

Solve for x:

36 (x - 5) = 9 x - 18

Expand out terms of the left hand side:

36 x - 180 = 9 x - 18

Subtract 9 x from both sides:

(36 x - 9 x) - 180 = (9 x - 9 x) - 18

36 x - 9 x = 27 x:

27 x - 180 = (9 x - 9 x) - 18

9 x - 9 x = 0:

27 x - 180 = -18

Add 180 to both sides:

27 x + (180 - 180) = 180 - 18

180 - 180 = 0:

27 x = 180 - 18

180 - 18 = 162:

27 x = 162

Divide both sides of 27 x = 162 by 27:

(27 x)/27 = 162/27

27/27 = 1:

x = 162/27

The gcd of 162 and 27 is 27, so 162/27 = (27×6)/(27×1) = 27/27×6 = 6:

Answer:  x = 6

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Hey there :)

Writing in scientific notation means a should be
0 ≤ a < 10

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3 is the 4th decimal place value

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point a is at (-7 5) and point c is at (5 -1). find the coordinates of point b on line ab such that ab is 5 times as long as bc
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Step-by-step explanation:

Let the coordinates of point b be (x,y).

Given the coordinates of a (-7,5) and c(5,-1)

Now according to question

ab = 5bc

using distance formula

\sqrt{(x+7)^2+(y-5)^2} =5\sqrt{(5-x)^2+(-1-y)^2}

Solving we can get

x=-\frac{-11+\sqrt{-4y^2-10y+25}}{2},\:x=\frac{\sqrt{-4y^2-10y+25}+11}{2}'

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Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
Verizon [17]
A) 0.9803; 0.4803
B) 32

We calculate the z-score for this problem by using the formula:

z=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}

Using our formula, we have:

z=\frac{3.00-2.65}{\frac{0.85}{\sqrt{25}}}=2.06

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.9803.

To find the probability it is between the mean and this, we subtract the probability associated with the mean (0.5) from this:
0.9803 - 0.5 = 0.4803.

To find B, we first find the z-score for this.  Using a z-table (http://www.z-table.com) we see that the closest z-score would be 2.33.  We then set up our equation as

2.33=\frac{3.00-2.65}{\frac{0.85}{\sqrt{n}}}=\frac{0.35}{\frac{0.85}{\sqrt{n}}}&#10;\\&#10;\\2.33=0.35\div \frac{0.85}{\sqrt{n}}=0.35\times \frac{\sqrt{n}}{0.85}

Multiplying both sides by 0.85 we have
2.33(0.85) = 0.35√n
1.9805 = 0.35√n

Divide both sides by 0.35:
1.9805/0.35 = √n

Square both sides:
(1.9805/0.35)² = n
32 ≈ n
8 0
3 years ago
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