p = latm
t = 273.15K
R= 0.08206 L atm mol K
75.0g02
16.00 (O₂) = 4.6875mol mol
9
Ideal gas law: PV = nRT, solve for volume: V = nRT P
V =
4.6875mol 0.08206 L-atm mol. K · 273.15K
V = 105L
latm
The reaction is spontaneous at high temperatures, and non-spontaneous at low temperatures.
In a thermodynamically closed system, the measure of the non-expansion work by the system and the enthalpy and the entropy is said to be the <u>Gibbs free energy</u>.
<h3>How to determine the Gibbs free energy?</h3>
According to the reaction, the enthalpy change
and the change in the entropy
is positive. The Gibbs free energy is given by,
and the reaction will be spontaneous only when the
is negative.
If there is not much effect on the enthalpy and entropy due to a decrease in temperature, then the value of the Gibbs free energy will be positive and will be close to that of the enthalpy change. In the above reaction enthalpy, change is positive and hence the reaction will be non-spontaneous.
When the temperature is increased then the entropy will affect the overall reaction as the Gibbs free energy will have the opposite sign as that of the entropy. So the reaction will become spontaneous at high temperatures.
Thus, option A is correct.
Learn more about Gibbs free energy here:
brainly.com/question/7988114
Answer:
58.44 g/mol
Explanation:
just got done with this unit two weeks ago
Answer:
C
Explanation:
The number of particles of any kind in 1 mol is 6.02*10^23.
How you modify that depends on the units.
The number of molecules in 1 mole of hydrogen is 6.02*10^23 molecules.
Each molecule consists of 2 atoms. Pure hydrogen at STP will have a multiplier of 2.
So the number of atoms is 2*6.02 * 10^23 = 1.20 * 10^24 atoms.