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jonny [76]
3 years ago
15

All the substances listed below are fertilizers that contribute nitrogen to the soil.

Chemistry
1 answer:
kvv77 [185]3 years ago
4 0

Answer:

Ammonia is the richest source of nitrogen on a mass percentage basis because it has 82.35% of nitrogen by mass.

Explanation:

Percentage of element in compound :

=\frac{\text{number of atoms}\times text{Atomic mass}}{\text{molar mas of compound}}\times 100

(a) Urea, (NH_2)_2CO

Molar mass of urea = 60 g/mol

Atomic mass of nitrogen = 14 g/mol

Number of nitrogen atoms = 2

N\%=\frac{2\times 14 g/mol}{60 g/mol}\times 100=46.67\%

(b) Ammonium nitrate, NH_4NO_3

Molar mass of ammonium nitrate = 80 g/mol

Atomic mass of nitrogen = 14 g/mol

Number of nitrogen atoms = 2

N\%=\frac{2\times 14 g/mol}{80 g/mol}\times 100=35.00\%

(c) Nitric oxide, NO

Molar mass of nitric oxide  = 30 g/mol

Atomic mass of nitrogen = 14 g/mol

Number of nitrogen atoms = 1

N\%=\frac{1\times 14 g/mol}{30 g/mol}\times 100=46.67\%

(d) Ammonia, NH_3

Molar mass of ammona = 17 g/mol

Atomic mass of nitrogen = 14 g/mol

Number of nitrogen atoms = 1

N\%=\frac{1\times 14 g/mol}{17 g/mol}\times 100=82.35\%​

Ammonia is the richest source of nitrogen on a mass percentage basis because it has 82.35% of nitrogen by mass.

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SIZIF [17.4K]

A combustion reaction is a reaction that reacts in the presence of oxygen molecules. Methane will release -3115 kJ/mol of heat.

<h3>What is a combustion reaction?</h3>

A combustion reaction includes the reaction between the chemical reactant and oxygen molecule to produce the product. The combustion reaction between methane and oxygen is given as:

CH₄(g) + 2O₂ (g) → CO₂(g) + 2H₂O (l), ΔH = -890 kJ/mol

The stoichiometry coefficient from the reaction gives 1 mole of methane releases -890 kJ/mol enthalpy.

So, 3.5 moles methane will release = 3.5 × -890 = -3115 kJ/mol

Therefore, -3115 kJ/mol of heat is released.

Learn more about combustion reaction here:

brainly.com/question/27823881

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4 0
2 years ago
which of the following will stay constant,no matter is the substance is in a solid,liquid,or gas states
Vlada [557]
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6 0
3 years ago
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The electrolysis of water forms H2 and O2. 2H2O Right arrow. 2H2 O2 What is the percent yield of O2 if 10.2 g of O2 is produced
Mama L [17]

Answer:

67.5%

Explanation:

Step 1: Write the balanced equation for the electrolysis of water

2 H₂O ⇒ 2 H₂ + O₂

Step 2: Calculate the theoretical yield of O₂ from 17.0 g of H₂O

According to the balanced equation, the mass ratio of H₂O to O₂ is 36.04:32.00.

17.0 g H₂O × 32.00 g O₂/36.04 g H₂O = 15.1 g O₂

Step 3: Calculate the percent yield of O₂

Given the experimental yield of O₂ is 10.2 g, we can calculate its percent yield using the following expression.

%yield = (exp yield / theoret yield) × 100%

%yield = (10.2 g / 15.1 g) × 100% = 67.5%

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3 years ago
Calculate the mass of h2o and c6 h12 o6 required to make 250 gram of 40% solution of glucose
Sedaia [141]
40% solution of glucose is where the solution contains, by weight, 40% glucose and 60% water. 

Therefore, if the total weight of the solution is 250 g, 
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mass of water (H2O) = 250 g * 60% = 150 g

Mass of water can also be calculated by subtracting the weight of glucose from the total weight of the solution:
mass of water = 250g-100g = 150g.
5 0
3 years ago
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lina2011 [118]
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