How many calories of heat were added to 347.9 g of water to raise its temperature from 25oC to 55oC?
1 answer:
Answer:
10437calories
Explanation:
The following data were obtained from the question given:
M = 347.9g
C = 4.2J/g°C
T1 = 25°C
T2 = 55°C
ΔT = 55 — 25 = 30°C
Q =?
Q = MCΔT
Q = 347.9 x 4.2 x 30
Q = 43835.4J
Converting this to calories, we obtained the following:
4.2J = 1 calorie
43835.4J = 43835.4/ 4.2 = 10437calories
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