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Natalija [7]
2 years ago
13

How many calories of heat were added to 347.9 g of water to raise its temperature from 25oC to 55oC?

Chemistry
1 answer:
saw5 [17]2 years ago
5 0

Answer:

10437calories

Explanation:

The following data were obtained from the question given:

M = 347.9g

C = 4.2J/g°C

T1 = 25°C

T2 = 55°C

ΔT = 55 — 25 = 30°C

Q =?

Q = MCΔT

Q = 347.9 x 4.2 x 30

Q = 43835.4J

Converting this to calories, we obtained the following:

4.2J = 1 calorie

43835.4J = 43835.4/ 4.2 = 10437calories

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2 years ago
A 0.0000792 M sample of Compound X in a solvent has an absorbance of 0.341 at 528 nm in a 1.000-cm cuvet. The solvent alone has
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b) C = 0,000127 M

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Lambert-Beer law says that there is a linear relationship between absorbance and concentration of a chemical substance. The formula is:

A = a×b×C

Where A is absorbance, a is molar absorptivity, b is path length and C is concentration.

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<em>a = 3485 M⁻¹cm⁻¹</em>

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<em></em>

I hope it helps!

8 0
3 years ago
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Answer:

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