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3 years ago

"Which particle builds a static electric charge when it is transferred from one object to another?

1 answer:

5 0

When two things rub against each other and become charged, it is
electrons that been rubbed off of one thing and on to the other one.

Protons would do that too if they got moved from one thing to another
by rubbing, but they don't.

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A point on a wheel of radius 40 cm that is rotating at a constant 5.0 revolutions per second is located 0.20 m from the axis of

Margarita [4]

Answer:

$197.2 m/s^2$

Explanation:

The centripetal acceleration of a point moving by circular motion is given by:

$a=\omega^2 r$

where

$\omega$ is the angular velocity

r is the distance from the axis of rotation

The point on the wheel makes 5.0 revolutions per second, so the frequency is

$f=\frac{5}{1}=5 Hz$

and the angular velocity is

$\omega=2\pi f = 2\pi (5)=31.4 rad/s$

While the distance of the point from the axis of rotation is

$r=0.20 m$

Substituting, we find the acceleration:

$a=(31.4)^2(0.20)=197.2 m/s^2$

5 0

3 years ago

Read 2 more answers

A Huge water tank is 2m above the ground if the water level on it is 4.9m high and a small opening is there at the bottom then t

lapo4ka [179]

Answer:

The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.

Explanation:

Let assume the existence of a line of current between the water tank and the ground and, hence, the absence of heat and work interactions throughout the system. If water is approximately at rest at water tank and at atmospheric pressure ( $P_{atm}$ ), then speed of efflux of the non-viscous water is modelled after the Bernoulli's Principle:

$P_{1} + \rho\cdot \frac{v_{1}^{2}}{2} + \rho\cdot g \cdot z_{1} = P_{2} + \rho\cdot \frac{v_{2}^{2}}{2} + \rho\cdot g \cdot z_{2}$

Where:

$P_{1}$ , $P_{2}$ - Water total pressures inside the tank and at ground level, measured in pascals.

$\rho$ - Water density, measured in kilograms per cubic meter.

$g$ - Gravitational acceleration, measured in meters per square second.

$v_{1}$ , $v_{2}$ - Water speeds inside the tank and at the ground level, measured in meters per second.

$z_{1}$ , $z_{2}$ - Heights of the tank and ground level, measured in meters.

Given that $P_{1} = P_{2} = P_{atm}$ , $\rho = 1000\,\frac{kg}{m^{3}}$ , $g = 9.807\,\frac{m}{s^{2}}$ , $v_{1} = 0\,\frac{m}{s}$ , $z_{1} = 6.9\,m$ and $z_{2} = 4.9\,m$ , the expression is reduced to this:

$\left(9.807\,\frac{m}{s^{2}} \right)\cdot (6.9\,m) = \frac{v_{2}^{2}}{2} + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.9\,m)$

And final speed is now calculated after clearing it:

$v_{2} = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (6.9\,m-4.9\,m)}$

$v_{2} \approx 6.263\,\frac{m}{s}$

The speed of efflux of non-viscous water through the opening will be approximately 6.263 meters per second.

5 0

4 years ago

What is the frequency of a wave?

Andrei [34K]

It is the number of waves passing a point in a certain time.

5 0

3 years ago

Read 2 more answers

The acceleration of the body in the graph given below is____

Art [367]

Acceleration = -12 / 8 = - .... m/s^2

5 0

3 years ago

The maximum displacement of an oscillatory motion is A=0.49m. Determine the position x at which the kinetic energy of the partic

Tatiana [17]

Answer:

The position x, is ± 0.4 m.

Explanation:

The total mechanical energy of the oscillatory motion is given as;

$E_T = U +K.E\\\\E_T = \frac{1}{2} kA^2\\\\ \frac{1}{2} kA^2 = U +K.E\\\\K.E = \frac{1}{2} kA^2 - U ----equation(1)$

When the kinetic energy (E) is half of the elastic potential energy (U);

$K.E = \frac{U}{2} ----equation(2)$

Equate (1) and (2)

$\frac{U}{2} = \frac{1}{2} kA^2 - U\\\\U = kA^2 -2U\\\\U+2U = kA^2\\\\3 U = kA^2\\\\3(\frac{1}{2} kx^2) = kA^2\\\\\frac{3}{2} x^2=A^2\\\\x^2 = \frac{2}{3} A^2\\\\x = \sqrt{\frac{2}{3} A^2} \\\\x = A\sqrt{\frac{2}{3} } \\\\x = 0.49\sqrt{\frac{2}{3} }\\\\x = + /- (0.4 \ m)$

Thus, the position x, is ± 0.4 m.

8 0

3 years ago