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White raven [17]
3 years ago
9

If the object represented by the FBD below has a mass of 2.0 kg, what is the

Physics
1 answer:
ycow [4]3 years ago
4 0

Answer: B

Explanation:

Let us first resolve the forces.

Horizontal, the vectorial resolution is equal to zero. Since the positive direction and negative direction vector are of same magnitude. Therefore, summation of horizontal forces Fh = 0

Vertical resolution, the sum of forces will be Fv = 30 - 35 = - 5 N

Resultant force F = sqrt( Fv^2 + Fh^2)

Substitutes Fv and Fh. We get

R = sqrt ( 25) = 5N

We are given that the mass M = 2kg

From Newton second law,

F = Ma

Where a = acceleration

Substitute F and M and make a the subject of formula

5 = 2a

a = 5/2 = 2.5 m/s^2

Therefore, acceleration a of the object is 2.5 m/s^2 down.

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Sound is a type of mechanical wave and must have a medium through which to travel. Sound will move at different speeds when whic
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Hey there!

The answer would be B. The sound moves from air to water.

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A brand of earplugs reduces the sound intensity level by 27 dB.By what factor do these earplugs reduce the acoustic intensity?
Fofino [41]

Answer:

Explanation:

27dB = 2.7 B

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= 1.99 X 10⁻³

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3 0
3 years ago
A uniform marble rolls down a symmetric bowl, starting from rest atthe top of the left side. The top of each side is a distanceh
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A. 5/7h

B. Same height

C. See attachment below

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Find the attachment below for better understanding.

7 0
3 years ago
A 0.01 kg spring toy is compressed 0.02 m and released vertically. The toy is measured to reach 0.25 m in the air. Determine the
Scorpion4ik [409]

Answer:

122.5 N/m

Explanation:

According to the law of conservation of energy, if there is no air resistance or frictional forces, the initial elastic potential energy of the spring toy is entirely converted into gravitational potential energy when the toy reaches the highest point.

Therefore, we can write:

\frac{1}{2}kx^2=mgh

where the term on the left is the initial elastic potential energy while the term on the right is the gravitational potential energy, and where

k is the spring constant

x = 0.02 m is the compression of the spring

m = 0.01 kg is the mass of the toy

h = 0.25 m is the height reached by the toy

g=9.8 m/s^2 is the acceleration due to gravity

Solving for k,

k=\frac{2mgh}{x^2}=\frac{2(0.01)(9.8)(0.25)}{(0.02)^2}=122.5 N/m

8 0
3 years ago
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