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3 years ago

I struggle in math, and occasionally I'll confuse the questions I try to answer

Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

15X=12X+12
Subtract 12X
3X=12
X=4

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Please explain step by step

Alja [10]

Let's find the value of x

Since the sum of internal angles of a triangle is 180°

therefore,

$\hookrightarrow \: (2x - 2) \degree + (x + 5) \degree + 90 \degree = 180 \degree$

$\hookrightarrow \: 2x - 2 \degree + x + 5\degree = 180\degree - 90\degree$

$\hookrightarrow \: 3x + 3\degree = 90\degree$

$\hookrightarrow \: 3(x + 1) = 3(30)$

$\hookrightarrow \: x + 1\degree = 30\degree$

$\hookrightarrow \: x = 29\degree$

4 0

3 years ago

How to solve 9x^2+9x+2

Oksana_A [137]

Answer:

factoring: ( 3 x + 1 ) ( 3 x+ 2 )

expressing/equation: 9x²= 81x

81x + 9x + 2=

9x+81x=90x

90x + 2

Step-by-step explanation:

7 0

3 years ago

14 divided 3/11 +14 x

slamgirl [31]

Answer:

14x+14/33

Step-by-step explanation:

14÷3/11+14x=

5 0

3 years ago

Evaluate the surface integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S f (x

kykrilka [37]

Parameterize $S$ by

$\vec s(u,v)=6\cos u\sin v\,\vec\imath+6\sin u\sin v\,\vec\jmath+6\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take a normal vector to $S$ ,

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=36\cos u\sin^2v\,\vec\imath+36\sin u\sin^2v\,\vec\jmath+36\cos v\sin v\,\vec k$

which has norm

$\left\|\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}\right\|=36\sin v$

Then the integral of $f(x,y,z)=x^2+y^2$ over $S$ is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\iint_S\left((6\cos u\sin v)^2+(6\sin u\sin v)^2\right)\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv$

$=\displaystyle36^2\int_0^{\pi/2}\int_0^{2\pi}\sin^3v\,\mathrm du\,\mathrm dv=\boxed{1728\pi}$

6 0

3 years ago

PLEASE HELP ME WITH THIS QUESTION

bonufazy [111]

Answer:

y-k

x-h

Step-by-step explanation:

Given E &D, F would be at (x, k).

That means E to F would be y-k.

And F to D would be x-h.

I assume you don’t need to find E to D, since that’s just r. (You could use the Distance Formula or Pythagoreans theorem to come up with and equation, but it wouldn‘t be one of those listed.)

7 0

3 years ago