I would pick the first option in the third option
The gas sample consists of CH₄ and He.
Number of CH₄ moles - 4 g/ 16 g/mol = 0.25 mol
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
Therefore 0.25 mol of CH₄ gas occupies a volume of 22.4 L/mol x 0.25 mol
Volume of methane - 5.6 L
Number of He moles - 2.00 g/ 4 g/mol = 0.5 mol
Volume occupied by He - 22.4 L /mol x 0.5 mol = 11.2 L
The total volume of the sample = 5.6 L + 11.2 L = 16.8 L
Answer:
6.022×1023 particles are present in one mole of a substance while about 7.5 x 1018 grains of sand are present on earth's beaches.
Explanation:
Mole is used in chemistry for the calculation of mass of an atom. 6.022×1023 particles are present in one mole of a substance while about 7.5 x 1018 grains of sand are present on earth's beaches. According to this data which shows that the size of mole is greater than the number of sand grains present on Earth’s beaches because there are higher particles are present in mole as compared to sand grains. So the mole has big size.
Lake water is favorable to Prokaryotic cell.
