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3 years ago

Solve ln 3 + ln (4x) = 4 round your answer to the nearest hundredth

2 answers:

3 0

Rewrite the equation in exponential form, use the definition of a log and then simplify and you should get x= e^4/12 or 4.55

Nataly [62]3 years ago

3 0

Answer:

x = 4.55.

Step-by-step explanation:

Given : ln 3 + ln (4x) = 4.

To find : Solve round your answer to the nearest hundredth.

Solution : We have given that

ln 3 + ln (4x) = 4.

By the logarithm rule : ln a + ln b = ln (ab).

Then,

ln 3 + ln (4x) = ln (3 * 4x )

ln 3 + ln (4x) = ln (12 x )

Then ,

ln (12 x ) = 4

Taking exponential both side

12x = $e^{4}$ .

12 x = 54.59.

12 x = 54 .59

On dividing by 12 both sides

x = 4.55.

Therefore, x = 4.55.

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Mr. Jensen is a salesperson for an insurance company. His monthly paycheck includes a base salary of $2,175 and a commission of

miss Akunina [59]

Answer:

y = 250x + 2175

Step-by-step explanation:

Mr. Jensen month pay = 2175

Commission per policy = 250

Let "x" be the number of policy he sells and "y" is the total paycheck including the commission.

y = 250x + 2175

7 0

4 years ago

he lengths of a particular animal's pregnancies are approximately normally distributed, with mean muequals252 days and standar

Rashid [163]

Answer:

Step-by-step explanation:

Let X be the lengths of a particular animal's pregnancies

X is N(252, 20)

(a) What proportion of pregnancies lasts more than 262 days?

$P(X>262) = 0.3085$

(b) What proportion of pregnancies lasts between 227 and 257 days?

$P(227$

P(X<237) = 0.2266

(d) A "very preterm" baby is one whose gestation period is less than 202 days. Are very preterm babies unusual?

$P(X$

Yes very unusual since probability is very near to 0.

7 0

4 years ago

Read 2 more answers

Plz help me with this...there might be errors in this but I'm not sure

Flura [38]

Step-by-step explanation:

1. cot(A − B)

From angle sum/difference equations, we know this equals:

cot(A − B) = (cot A cot B + 1) / (cot B − cot A)

But we also know it equals:

cot(A − B) = 1 / tan(A − B)

cot(A − B) = (1 + tan A tan B) / (tan A − tan B)

Setting the two equal to each other:

(cot A cot B + 1) / (cot B − cot A) = (1 + tan A tan B) / (tan A − tan B)

Writing tangent in terms of cotangent:

(cot A cot B + 1) / (cot B − cot A) = (1 + 1 / (cot A cot B)) / (tan A − tan B)

(cot A cot B + 1) / (cot B − cot A) = ((cot A cot B + 1) / (cot A cot B)) / (tan A − tan B)

(cot A cot B + 1) / (cot B − cot A) = (cot A cot B + 1) / ((cot A cot B) (tan A − tan B))

Divide both sides by the numerator:

1 / (cot B − cot A) = 1 / ((cot A cot B) (tan A − tan B))

Take inverse of both sides:

cot B − cot A = (cot A cot B) (tan A − tan B)

Solve for cot A cot B:

cot A cot B = (cot B − cot A) / (tan A − tan B)

cot A cot B = a / b

Now substitute into the first angle difference equation we wrote earlier:

cot(A − B) = (cot A cot B + 1) / (cot B − cot A)

cot(A − B) = (a / b + 1) / a

cot(A − B) = (a / b) / a + 1 / a

cot(A − B) = 1 / b + 1 / a

2. cos A / (1 ± sin A)

From angle sum/difference formulas, we know:

sin (90 ± A) = cos A

cos (90 ± A) = ∓ sin A

Substituting:

sin (90 ± A) / (1 − cos (90 ± A))

From half angle formula, this equals:

cot (45 ± A/2)

Using reflection:

-cot (-45 ∓ A/2)

And finally, phase shift:

tan (-45 ∓ A/2 + 90)

tan (45 ∓ A/2)

Check that you wrote the problem correctly. Looks like you switched ∓ with ±.

8 0

3 years ago

Help me please with 3 and 4

dezoksy [38]

X is equal to or greater than 3:

Plot x = 3 on the x-axis (horizontal axis). Then, beginning at x = 3, draw an arrow from there to the right.

8 0

3 years ago

Tyrone runs 5 mph how far can he travel in two hours and 30 minutes

zaharov [31]

Answer:

12.5 miles

Step-by-step explanation:

5x2.5=12.5 miles

5 0

3 years ago