Answer:
(a) x > 4 (b) y < -2
Step-by-step explanation:
Domain is referring to the x-values while the range is referring to the y-values.
Since the function (the line) has a circle at the point (4, -2), the function will be exclusive at that coordinate.
The line goes to infinity for the x-values from 4, so you write x > 4 or ∞ > x > 4.
Similarly, the line goes to infinity for the y-values from -2, so you write y < -2 or -∞ < y < -2.
Answer:
128
Step-by-step explanation:
5+2=7
5-2=3
2^5=32
2^2=4
32*4=128
Hope this helps:)
Answer:
Standard error = 0.4
Step-by-step explanation:
Step 1
We find the Standard Deviation
The formula = √(x - mean)/n - 1
n = 15
Mean = 1.93 hours
= √(0- 1.93)² + (0-1.93)² +(0- 1.93)²+( 0- 1.93)²+ (1- 1.93)² + (1- 1.93)² +(1 - 1.93)² +(2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + ( 2 - 1.93)² +(4 - 1.93)² +(4 - 1.93)² + (5 - 1.93)²/15 - 1
= √(3.737777776 + 3.737777776 + 3.737777776 + 0.871111111 +0.871111111 + 0.871111111 + 0.004444444445+ 0.004444444445 + 0.004444444445 + 0.004444444445 + 0.004444444445 + 1.137777778 + 4.271111112 + 4.271111112 + 9.404444446)/15 - 1
= √2.352380952
= 1.533747356
Step 2
We find the standard error
The formula = Standard Deviation/√n
Standard deviation = 1.533747356
n = 15
= 1.533747356/√15
= 1.533747356 /3.87298334621
= 0.39601186447
Approximately = 0.4
Therefore, the standard error is 0.4
Not on your list, but an easy way is
.. a) swap coefficients of x and y, negating one. (Now you have 2x -3y.)
.. b) set any constant term to zero (now you have 2x -3y = 0)
.. c) translate the line to the point (5, 2) by substituting x ⇒ x-5, y⇒ y-2
2(x -5) -3(y -2) = 0
The way you've been taught, selection C is the proper choice.
Answer:
<h2>This value is called the common difference</h2>
Step-by-step explanation:
The common difference is the constant value which is repeatedly added to each term in an arithmetic sequence to obtain the next term, it is basically the difference between consecutive numbers
To find the common difference we can subtract the previous term from the first time or the second to the last term from the last term, the idea of finding the common difference is basically subtracting the previous term form the subsequent term.
