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sattari [20]
3 years ago
12

Which atoms will bond when valence electrons

Chemistry
2 answers:
sergij07 [2.7K]3 years ago
7 0
Since Oxygen is in group 16, this element has 6 valence electrons. Valence electrons like to become as stable as possible and similar to a noble gas, which has 8 electrons. You need to find an element that will transfer its atoms to the oxygen to make 8 electrons. Looking at the periodic table, Selenium is in group 16 and will have 6 valence electrons (6 + 6 = 12). This can't transfer electrons with Oxygen. Hydrogen is in group 1 with 1 valence electron (6 + 1 = 7). This can't transfer electrons with Oxygen. Strontium is in group 2 with 2 valence electrons (6 + 2 = 8). This will transfer electrons to Oxygen, making it the most stable.

The answer is O and Sr. 
kvasek [131]3 years ago
3 0
Because the problem says valence electrons are transferred from one atom to the other, it has to be an "ionic" bond (it's not the "covalent" bond because electrons aren't shared with each other). As a matter of fact, an "ionic" bond is formed when a metal combines with a non-metal or a metalloid. Strontium (Sr) is an alkaline earth metal, which is also a metal, and Oxygen (O) is a non-metal. These two atoms will perfectly form (an) "ionic" bond(s). Therefore, option (2) O and Sr is correct.
Hope this would help :))
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answer D) VP# 1 and 3

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3 years ago
Solve the equation for n 0.0092=0.608 x (n/84.01)+n/52.5
kotegsom [21]

Answer:

      n\approx 0.350

Explanation:

<u>1. Rewrite the equation in a more appropriate format for a better understanding: </u>

0.0092=0.608\times \dfrac{n}{84.01}+\dfrac{n}{52.5}

<u />

<u>2. Multiply the whole equation (both sides) by 84.01 × 52.5 to eliminate the denominators:</u>

      0.0092\times 84.01\times 52.5=0.608\times 52.5n+84.01n

<u>3. Do the operations:</u>

          40.57683=31.92n+84.01n

<u>4. Add like terms:</u>

      40.57683=115.93n

<u />

<u>5. Divide both sides by 115.93:</u>

    0.350011\approx n\\\\n\approx 0.350011\\\\n\approx 0.350

3 0
4 years ago
Which of the following statements is true?
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3 years ago
When a mixture of glucose 6-phosphate and fructose 6-phosphate is incubated with the enzyme phosphohexose isomerase, the final m
Anastasy [175]

Answer:

The correct option is B

Explanation:

The reaction is given as

             Glucose\ 6-phosphate ---->fractose \ 6-phosphate

The equilibrium constant for this reaction is mathematically represented as

               K_c = \frac{[concentration \ of  \ product ]}{concentration \ of  \ reactant } = \frac{[fructose \ 6 -phosphate]}{[Glucose \ 6 - phosphate]}

From the question we are told that

    [Glucose 6-phosphate] = 2 × [fructose 6-phosphate]

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      K_c  = \frac{[fructose \ 6 -phosphate]}{[2 (fructose \ 6 -phosphate)]} = 0.5

Generally change in free energy \Delta G is mathematically represented as

          \Delta G = - RTlnK_c

Given that T = 298 K

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               = -1717.32 J/mol

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5 0
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