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3 years ago

Which atoms will bond when valence electrons

2 answers:

7 0

Since Oxygen is in group 16, this element has 6 valence electrons. Valence electrons like to become as stable as possible and similar to a noble gas, which has 8 electrons. You need to find an element that will transfer its atoms to the oxygen to make 8 electrons. Looking at the periodic table, Selenium is in group 16 and will have 6 valence electrons (6 + 6 = 12). This can't transfer electrons with Oxygen. Hydrogen is in group 1 with 1 valence electron (6 + 1 = 7). This can't transfer electrons with Oxygen. Strontium is in group 2 with 2 valence electrons (6 + 2 = 8). This will transfer electrons to Oxygen, making it the most stable.

The answer is O and Sr.

kvasek [131]3 years ago

3 0

Because the problem says valence electrons are transferred from one atom to the other, it has to be an "ionic" bond (it's not the "covalent" bond because electrons aren't shared with each other). As a matter of fact, an "ionic" bond is formed when a metal combines with a non-metal or a metalloid. Strontium (Sr) is an alkaline earth metal, which is also a metal, and Oxygen (O) is a non-metal. These two atoms will perfectly form (an) "ionic" bond(s). Therefore, option (2) O and Sr is correct.
Hope this would help :))

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Pyridine, C5H5N, is a polar organic solvent. How many carbon atoms are in 7.05 moles of pyridine? 4.24 x 1024 4.24 x 10, 24 2.12

leonid [27]

Answer:

2.122×10^25atoms

Explanation:

number of moles=mass/molar mass

7.05moles= mass of pyridine/79

reacting mass of pyridine=556.95

C5H5N= (12×5)+(5)+(14)=79

C5=60

to find the mass of carbon in 556.95g of pyridine we take the stoichometric ratio

60[C5] -----> 79[C5H5N]

x[C5] --------> 556.95g[C5H5N]

cross multiply

x=(60×556.95)/79

x=423g of carbon

moles=mass/molar mass

moles of carbon=423/12

moles=35.25moles of carbon

moles=number of particles/Avogadro's constant

35.25=number of particles/6.02×10^23

number of particles=2.122×10^25atoms of carbon

3 0

3 years ago

SOMEONE HELO PLZ!!!!!

umka21 [38]

Answer:

2 8 8 2 is a correct answer

7 0

3 years ago

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

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3 years ago

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Wha do u do when u get in a fight wit yo best friend?

antiseptic1488 [7]

Talk to them and listen to each other. if they aren’t ready to talk, give them space. once both of you are ready, you can make up and forgive each other. don’t bother them by asking a lot of questions and forcing them to talk to you. and if they’re doing that, tell them you need time to think. just be sure to talk to them, listen, and understand. tell each other both sides of the stories. of course, different situations can require different solutions. so resolve it when it’s time :)

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3 years ago

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Asprin can be made by adding 200.0 g of salicylinc

damaskus [11]

Correct, Was that a question.

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3 years ago