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Dominik [7]
3 years ago
5

1. A sample of oxygen is collected over water at 22 ° C and 762 torr. What is the partial pressure of the dry oxygen? The vapor

pressure of water at 22°C is 19.8 torr. A. 742 torr B. 782 torr C. 784 torr D. 750. Torr
Chemistry
1 answer:
Rom4ik [11]3 years ago
8 0

Answer: The partial pressure of the dry oxygen is 742 torr

Explanation:

Dalton's Law of Partial Pressure states that the total pressure exerted by a mixture of gases is the sum of partial pressure of each individual gas present. Thus P(total)=P_1+P_2 .........

Given; Total pressure = 762 torr

partial pressure of water = 19.8 torr

partial pressure of dry oxygen = ? torr

Total pressure  = partial pressure of water + partial pressure of dry oxygen

762 torr = 19.8 torr = partial pressure of dry oxygen

partial pressure of dry oxygen = 742 torr

The partial pressure of the dry oxygen is 742 torr

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Answer:

1.852 g of CO2 were produced in the chemical reaction

Explanation:

The problem is pretty simple. We can write down the chemical reaction that is involved to help us understand better what is going on in the process:

CaCO3 (aq) + HAc (aq) → CaAc (aq) + CO2 (g) + H2O (l)

Let's think this through: we have a tablet that has an active compound (CaCO3) and an inert substance that weighs 0.833 g. When we add 58.072 g of an acid solution (represented in the equation as HAc because we are not told specifically which acid is being added), CO2 is formed and released from solution as gas leaving us with an aqueous solution that weighs 57.053 g.

Having said that, we know that the only mass lost during the reaction is due to the formation of CO2 gas. Therefore, we sum the reactants (the tablet + the acid solution) and subtract the mass of the remnant solution. This value will indicate us the amount of CO2 formed:

0.833 g of the Tablet + 58.072 g from the Acid solution = 58.905 g

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