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bogdanovich [222]
3 years ago
14

How many moles of mgs2o3 are in 193 g of the compound?

Chemistry
1 answer:
Mashutka [201]3 years ago
8 0

Answer:

             1.414 Moles

Solution:

Data Given:

                 Mass of MgS₂O₃  =  193 g

                 M.Mass of MgS₂O₃  =  136.43 g.mol⁻¹

                 Moles  =  ?

Formula Used:

                            Moles  =  Mass ÷ M.Mass

Putting values,

                            Moles  =  193 g ÷ 136.43 g.mol⁻¹

                            Moles =  1.414 mol

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Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

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Thus, by combining them, we obtain:

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y=mx+b

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It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

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