(a) Reaction of nitric acid with non-metal:
C+4HNO
3

⟶CO
2

+2H
2

O+4NO
2

S+6HNO
3

⟶H
2

SO
4

+2H
2

O+6NO
2

(b) Nitric acid showing acidic character:
K
2

O+2HNO
3

⟶2KNO
3

+H
2

O
ZnO+2HNO
3

⟶Zn(NO
3

)
2

+H
2

O
(c) Nitric acid acting as oxidizing agent
P
4

+20HNO
3

⟶4H
3

PO
4

+4H
2

O+20NO
2

3Zn+8HNO
3

⟶3Zn(NO
3

)
2

+4H
2

O+2NO

hope that helps you please mark brainliest

3 0

3 years ago

the white powder is added to the clear liquid. what event is occurring and is it a physical or chemical change?

alexdok [17]

I would say chemical but I’m not 100% sure might wanna get a second opinion

7 0

3 years ago

Read 2 more answers

CAN SOMEONE PLEASE PLEASE PLEASE ANSWER MY FOUR MOST RECENT QUESTIONS PLEASEEEEEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

SpyIntel [72]

Put a picture there’s nothing here

7 0

3 years ago

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

posledela

The question is incomplete, here is the complete question:

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

$2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag$

Suppose 6 moles of silver nitrate react. The reaction consumes___ moles of copper. The reaction produces __ moles of copper(II) nitrate and __ moles of silver.

Answer: The amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

Explanation:

We are given:

Moles of silver nitrate = 6 moles

For the given chemical reaction:

$2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag$

For copper metal:

By Stoichiometry of the reaction:

2 moles of silver nitrate reacts with 1 mole of copper metal

So, 6 moles of silver nitrate will react with = $\frac{1}{2}\times 6=3mol$ of copper metal

Moles of copper reacted = 3 moles

For copper(II) nitrate:

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 1 mole of copper(II) nitrate

So, 6 moles of silver nitrate will produce = $\frac{1}{2}\times 6=3mol$ of copper(II) nitrate

Moles of copper(II) nitrate produced = 3 moles

For silver metal:

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of silver metal

So, 6 moles of silver nitrate will produce = $\frac{2}{2}\times 6=6mol$ of silver metal

Moles of silver metal produced = 3 moles

Hence, the amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

6 0

4 years ago