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alexdok [17]
3 years ago
11

Which one of the following types of training involves 10 to 30 minutes of high-intensity exercise?

Physics
2 answers:
Goshia [24]3 years ago
5 0

Correct answer choice is:



C. Medium range



Explanation:



Medium range exercises are used to gain extra strength and fitness. Usually, heavyweights are used with less number of repetitions. These sort of exercises are mostly the hardest t do. All you need is to have a high level of motivation and stamina, which can be gained by running or cycling.

Evgen [1.6K]3 years ago
4 0

Answer:

c. medium range

Explanation:

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The current in a lamp is 0.5 ampere when it is plugged into a standard wall outlet. What is the resistance of the lamp when it i
lidiya [134]

The resistance of the lamp plugged in to a standard wall outlet with a current of 0.5 amps is 240 Ω (ohms)

Explanation:

In the United States Of America the standard voltage is 120 v and their frequency is 60 Hz

Standard wall outlet voltage is 120 V

The current in the lamp is 0.5 ampere

Resistance (R) = V/ I

      = 120/0.5

      = 240Ω (ohms)

Thus the resistance of the lamp plugged in to a standard wall outlet with a current of 0.5 amps is 240 Ω (ohms).

8 0
3 years ago
A 1000-kilogram car traveling due east at 15 meters per second hit from behind and receives a forward impulse of 6000 newton-sec
strojnjashka [21]

The change in momentum of the car is 6000 kg m/s

Explanation:

According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on the object, therefore:

\Delta p = I

where

\Delta p is the change in momentum

I is the impulse exerted

For the car in this problem, the impulse received is

I = 6000 kg m/s (in the forward direction)

Therefore, the change in momentum of the car is equal to this value:

\Delta p = I = 6000 kg m/s (in the forward direction)

We can also calculate what is the new momentum of the car. In fact, the initial momentum is

p_i = mu = (1000 kg)(15 m/s)=15,000 kg m/s

And  so, the new momentum is

p_f = p_i + \Delta p = 15,000 + 6,000 = 21,000 kg m/s

Learn more about impulse and momentum:

brainly.com/question/9484203

#LearnwithBrainly

8 0
3 years ago
Two bicycle tires are set rolling with the same initial speed of 4.0 m/s along a long, straight road, and the distance each trav
umka2103 [35]

Answer:

The coefficient of rolling friction will be "0.011".

Explanation:

The given values are:

Initial speed,

v_i = 4.0 \ m/s

then,

v_f=\frac{4.0}{2}

    =2.0 \ m/s

Distance,

s = 18.2 m

The acceleration of a bicycle will be:

⇒ a=\frac{v_f^2-v_i^2}{2s}

On substituting the given values, we get

⇒    =\frac{(2.0)^2-(4.0)^2}{2\times 18.2}

⇒    =\frac{4-8}{37}

⇒    =\frac{-4}{37}

⇒    =0.108 \ m/s^2

As we know,

⇒  f=ma

and,

⇒  \mu_rmg=ma

⇒       \mu_r=\frac{a}{g}

On substituting the values, we get

⇒       =\frac{0.108}{9.8}

⇒       =0.011

7 0
3 years ago
PLEASE HELP IM CONFUSED
tamaranim1 [39]
Its B. Hope this helped :) ♥♥
8 0
3 years ago
Small cubes that are 10 cm on a side and larger ones that are 12 cm on a side are submerged in water. Cubes A and B are made of
Digiron [165]

Answer

given,

given,

small cube side = 10 cm

larger cube side = 12 cm

density of steel = 7 g/cm³

density of aluminium = 2.7 g/cm³

density of the water (ρ₁)= 1 g/cm³

Cube A and B made of steel

buoyant force of Cube A

 B₁ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube B

 B₂ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force of Cube C

 B₃ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube D

 B₄ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force acting on the cube depends on the density of the fluid

hence,

B₂ = B₄  > B₁ = B₃

 

8 0
3 years ago
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