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Musya8 [376]
3 years ago
9

Todo sistema heterogêneo é bifásico

Physics
1 answer:
strojnjashka [21]3 years ago
3 0
I don't understand the language.....
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3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que
Eduardwww [97]

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

x=\frac{v_{i}^{2}sin(2\alpha)}{g} (1)

Donde:

  • v(i) es la velocidad inicial del cañon (82 m/s)
  • α es el ángulo de tiro
  • g es la gravedad (9.81 m/s²)
  • x es el desplazamiento total (560 m)

Lo que debemos hacer es depejar α de la ecuación 1

sin(2\alpha)=\frac{xg}{v_{i}^{2}}

sin(2\alpha)=\frac{560*9.81}{82^{2}}

sin(2\alpha)=0.82

\alpha=\frac{sin^{-1}(0.82)}{2}

\alpha=27.39^{\circ}

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

v_{x}=\frac{x}{t}

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

v_{i}cos(\alpha)=\frac{x}{t}

t=\frac{x}{v_{i}cos(\alpha)}

t=\frac{560}{82cos(27.39)}

t=7.69\: s

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

3 0
3 years ago
In a closed system, the total energy prior to an energy transformation is _______ the total energy after. A. equal to B. unrelat
jasenka [17]

Answer:

A) equal to

In a closed system, the total energy prior to an energy transformation is <u>equal to</u> the total energy after.

Explanation:

A closed system is defined as an isolated region surrounded by a boundary across which no transfer of matter or energy can take place.

Hence, even if there is an energy transformation in a closed system, the overall energy of the closed system remains constant.

3 0
4 years ago
The force of repulsion between two like-charged particles will increase if
Andru [333]
If the distance between the charged particles is deceased
6 0
4 years ago
Read 2 more answers
The electric force between two charged balloons is 0.16 newtons. If the distance between them is doubled, what will the new forc
lara31 [8.8K]
<span>So we wan't to know what will the Coulomb force be between two charged baloons will be if we double the distance between the them and Fc=0.16N. The coulomb force between two charges is Fc=k*Q1*Q2/r^2. So we see from the equation that the magnitude of the force will be smaller as we increase the distance. So let's increase the distance from r to R=2r. If we input thai into the equation we get: Fc=k*Q1*Q2/R^2. Now: Fc=k*Q1*Q2/(2r)^2. And finally: Fc= k*Q1*Q2/4r^2. And if we factor out 1/4 we get: Fc=(1/4)*k*Q1*Q2/r^2. Now we can see that if we double the distance the magnitude of the force will be smaller for a factor of 1/4 or the magnitude of the force will be smaller 4 times. So finally the force is (1/4)*0.16N= 0.04N. So the correct answer is A. 0.04 newtons. </span>
4 0
4 years ago
Read 2 more answers
Can a molecule have bond dipoles but not have a molecular dipole?
MissTica

Answer: Yes

Explanation: A molecule has a bond dipole but not have a molecular dipole.

Dipole moment:  dipole moment is the product of the distribution of the charge of the molecules and the distance between of the molecules.  

Example:  

lets take an example of  CO_{2} molecule in which two electro negative oxygen atoms are attached with Carbon atom. Oxygen being electro negative will attract the shared pair electrons towards itself and  partial negative charge will create on oxygen atom and partial positive charge on carbon atom C.

due to formation of partial positive and partial negative charges dipole moment is created between oxygen and Carbon bond on both the sides in opposite direction.

Since, the dipole moment acting in opposite direction the net dipole moment in the molecule is zero.

Hence, Yes, a molecule has bond dipoles but not have a molecular dipole.

8 0
4 years ago
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