Two blocks, 1 and 2, are connected by a rope R1 of negligible mass. A second rope R2, also of negligible mass, is tied to block

Question

3 years ago

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Two blocks, 1 and 2, are connected by a rope R1 of negligible mass. A second rope R2, also of negligible mass, is tied to block

2. A force is applied to R2 and the blocks accelerate forward. Is the magnitude of the force exerted by the rope R1 on block 1 larger, smaller, or equal to the magnitude of the force exerted by R2 on block 2?

Physics

1 answer:

o-na [289] · Answer 1 · 2022-05-02T00:11:22+03:00

Answer:

Smaller

Explanation:

Net force = Total mass * acceleration

If there is no friction, the net force is the tension in the second rope. Let’s assume the mass of each block is 2 kg, and the tension in the second rope is 8 N.

8 = 4 * a

a = 2 m/s^2

Since there is friction, the tension in the first rope is causing the first block to accelerate. To determine tension, use the following equation.

F = m * a

T = 2 * 2 = 4 N

If there is no friction and both blocks have the same mass, the tension in the second rope will be less than the tension in the first rope. I hope this helps you. If the masses are different, you can use this method to determine the tension in the first rope.