3 years ago

What is true about current?

Physics

2 answers:

stealth61 [152]3 years ago

7 0

Choices B, D, and E are all true statements.

hichkok12 [17]3 years ago

6 0

The answer is D. The current is measured on Amperes or Amps

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Elena L [17]

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3 years ago

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Find the current passing through each of the 3 resistors connected parallel to each other as shown in the figure (i1, i2, I3). S

Thepotemich [5.8K]

Answer:

I1 = ε/R1

I2 = ε/R2

I3 = ε/R3

Explanation:

From the image, we see that the resistors are connected in parallel. This means that the voltage passing through them is the same.

Now, formula for current is; I = V/R

In this case, V which is voltage is denoted by ε.

Thus;

I1 = ε/R1

I2 = ε/R2

I3 = ε/R3

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3 years ago

How will the electrostatic force between two electric charges change if the first charge is doubled and the second charge is onl

Vinvika [58]

Answer:

B) $\frac{2}{3}$

Explanation:

The electric force between charges can be determined by;

F = $\frac{kq_{1} q_{2} }{r^{2} }$

Where: F is the force, k is the Coulomb's constant, $q_{1}$ is the value of the first charge, $q_{2}$ is the value of the second charge, r is the distance between the centers of the charges.

Let the original charge be represented by q, so that;

$q_{1}$ = 2q

$q_{2}$ = $\frac{q}{3}$

So that,

F = $q_{1}$ $q_{2}$ x $\frac{k}{r^{2} }$

= 2q x $\frac{q}{3}$ x $\frac{k}{r^{2} }$

= $\frac{2q^{2} }{3}$ x $\frac{k}{r^{2} }$

= $\frac{2}{3}$ x $\frac{kq}{r^{2} }$

F = $\frac{2}{3}$ x $\frac{kq}{r^{2} }$

The electric force between the given charges would change by $\frac{2}{3}$ .

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3 years ago

In what two ways can we increase the potential difference?

vredina [299]

Yes I hope this helps

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Who was the man who lived from 460B.C. 370B.C. and was among the first to suggest the idea of atoms?

Jlenok [28]

C Democritus

That's the Answer

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