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Sindrei [870]
3 years ago
5

Write about a possible scenario where you may be tempted to not use lab safety explain what the correct and most safe choice wou

ld be in that situation
Physics
1 answer:
PtichkaEL [24]3 years ago
3 0
<span>One instance of forgoing lab safety would be a simple drop of a chemical into a test tube, and not wearing protective eye gear. Although it seems irrelevant to put on the goggles just for this matter, it is ultimately the safest option to do so in order to remain unharmed.</span>
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A current of 17 A flows through a resistor of 10 2. What is the voltage<br> across the resistor
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Ohms law V = IR

17 x 10 = 170V
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Science can only test questions that involve the natural world.
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An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the
poizon [28]

Answer:

The value is A  =  0.014 \  m

Explanation:

From the question we are told that

    The mass of the object is  m  =  2.0 \  kg

    The unstressed length of the string is  l  =  0.08 \  m

    The length of the spring when it is  at equilibrium is  l_e = 5.9 \  cm  =  0.059 \  m

      The initial speed (maximum speed)of the spring when given a downward blow v  =  0.30 \  m/s

Generally the maximum speed  of the spring  is mathematically represented as

           u =  A *  w

Here A is maximum height above the floor (i.e the maximum amplitude)

            and w is the angular frequency which is mathematically represented as

       w = \sqrt{\frac{k}{m} }

So

        u =  A *   \sqrt{\frac{k}{m} }

=>      A  =  u *   \sqrt{\frac{m}{k} }

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

           b  =  l -l_e

=>         b  = 0.08 - 0.05 9

=>         b  = 0.021 \  m

Generally at equilibrium position the net force acting on the spring is  

            k *  b  -  mg  =  0

=>         k *  0.021   -   2 * 9.8  =  0

=>        k =  933 \  N/m

So

            A  =  0.30  *   \sqrt{\frac{2}{933} }

=>          A  =  0.014 \  m

8 0
3 years ago
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