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2 years ago

5

Write about a possible scenario where you may be tempted to not use lab safety explain what the correct and most safe choice wou

ld be in that situation

1 answer:

PtichkaEL [24]2 years ago

3 0

<span>One instance of forgoing lab safety would be a simple drop of a chemical into a test tube, and not wearing protective eye gear. Although it seems irrelevant to put on the goggles just for this matter, it is ultimately the safest option to do so in order to remain unharmed.</span>

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Ask Your Teacher William Tell shoots an apple from his son's head. The speed of the 120-g arrow just before it strikes the apple

svlad2 [7]

Answer:

M = 0.115 kg

Explanation:

given,

mass of arrow = 120 g = 0.12 Kg

speed of arrow before it strike apple = 29.7 m/s

distance traveled by the arrow stick combination = 9.30 m

height of the son = 1.85 m

weight of the apple = ?

now,

time of flight of arrow and apple combination

using equation of motion

$h = u t + \dfrac{1}{2}gt^2$

$h = \dfrac{1}{2}gt^2$

$t = \sqrt{\dfrac{2h}{g}}$

$t = \sqrt{\dfrac{2\times 1.85}{9.8}}$

t = 0.614 s

$speed = \dfrac{distance}{time}$

$s = \dfrac{9.30}{0.614}$

s = 15.15 m/s

using conservation of momentum

m v = (M+ m) s

0.12 x 29.7 = (M+ 0.12) x 15.15

M+ 0.12 = 0.235

M = 0.115 kg

mass of apple is equal to 0.115 Kg

6 0

2 years ago

Thermopane window is constructed, using two layers of glass 4.0 mm thick, separated by an air space of 5.0 mm.

Bond [772]

To solve this problem it is necessary to apply the concepts related to rate of thermal conduction

$\frac{Q}{t} = \frac{kA\Delta T}{d}$

The letter Q represents the amount of heat transferred in a time t, k is the thermal conductivity constant for the material, A is the cross sectional area of the material transferring heat, $\Delta T$ , T is the difference in temperature between one side of the material and the other, and d is the thickness of the material.

The change made between glass and air would be determined by:

$(\frac{Q}{t})_{glass} = (\frac{Q}{t})_{air}$

$k_{glass}(\frac{A}{L})_{glass} \Delta T_{glass} = k_{air}(A/L)_{air} \Delta T_{air}$

$\Delta T_{air} = (\frac{k_{glass}}{k_{air}})(\frac{L_{air}}{L_{glass}}) \Delta T_{glass}$

$\Delta T_{air} = (\frac{0.84}{0.0234})(\frac{5}{4}) \Delta T_{glass}$

$\Delta T_{air} = 44.9 \Delta T_{glass}$

There are two layers of Glass and one layer of Air so the total temperature would be given as,

$\Delta T = \Delta T_{glass} +\Delta T_{air} +\Delta T_{glass}$

$\Delta T = 2\Delta T_{glass} +\Delta T_{air}$

$20\°C = 46.9\Delta T_{glass}$

$\Delta T_{glass} = 0.426\°C$

Finally the rate of heat flow through this windows is given as,

$\Delta {Q}{t} = k_{glass}\frac{A}{L_{glass}}\Delta T_{glass}$

$\Delta {Q}{t} = 0.84*24*10 -3*0.426$

$\Delta {Q}{t} = 179W$

Therefore the correct answer is D. 180W.

3 0

2 years ago

how to use GRASS to answer this question: What voltage produces a current of 500A with a resistance of 50 ohms?

Pavel [41]

Answer:

oh my days ‍♂️this is so weird

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2 years ago

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Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiment

Drupady [299]

Answer:

$u_K=0.862$

Explanation:

The force of friction between the quails feet and the ground is:

$F=m*a$

$F_K=m*a$

$F_K=u_k*m*g$

$u_K*m*g=m*a_c$

$u_K*g=a$

$u_K=\frac{a_c}{g}$

$a_c=\frac{v^2}{r}$

So the coefficient of static is solve

$u_K=\frac{\frac{v^2}{r}}{g}$

$u_K=\frac{v^2}{r*g}=\frac{(2.6m/s)^2}{0.80m*9.8m/s^2}$

$u_K=0.862$

4 0

2 years ago

Please help me answer this question

Pavel [41]

It can either be all of them or just 1 and 3

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2 years ago