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goldfiish [28.3K]

2 years ago

15

Six bags weigh 120 g. How much do five bags weigh? Answer in grams. *

2 answers:

aleksandrvk [35]2 years ago

7 0

6 bags=120g

5 bags=xg

$\dfrac{6}{5} =\dfrac{120}{x} \\\\x=\dfrac{5*120}{6} \\x=100$

Answer: 5 bags weigh 100g

Jet001 [13]2 years ago

4 0

Answer:

100 grams

Step-by-step explanation:

6 bags ................. 120 g

5 bags ......................x g

x = 5×120/6 = 600/6 = 100 grams

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2 years ago

Find the greatest common divisor of 100 and 254, using • prime factorization- • euclidean algorithm-

larisa [96]

Via prime factorization:

$100=10^2=2^2\cdot5^2$
$254=2\cdot127$

of which the only common factor is a single power of 2, so $\mathrm{gcd}(100,254)=2$ .

Via the Euclidean algorithm:

$254=2\cdot100+54$
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4 0

3 years ago

Phil's height is 51.2 cm, suzanne's height is 5'4", and suzanne's shadow lengthat gobblers knob is 76.2

8090 [49]

Answer:

$P_1 = 24cm$

Step-by-step explanation:

Represent:

Phil's height with P

Suzanne's height with S

Phil's shadow with P1

Suzanne's shadow with S1

So, we have:

$P = 51.2cm$

$S = 5'4"$

$S_1 = 76.2cm$

Required

Calculate the length of Phil's shadow --- Missing part of question

To do this, we make use of the following equivalent ratio.

$P:S = P_1 : S_1$

Convert $S = 5'4"$ to cm

$S = 5ft\ 4in$

$S = (5*30.48+ 4*2.54)cm$

$S = 162.56cm$

Substitute values for P, S and S1

$51.2cm : 162.56cm = P_1 : 76.2cm$

Express as fraction

$\frac{51.2cm}{162.56cm} = \frac{P_1 }{ 76.2cm}$

Make P1 the subject

$P_1 = 76.2cm * \frac{51.2cm}{162.56cm}$

$P_1 = 76.2cm * \frac{51.2}{162.56}$

$P_1 = \frac{76.2cm * 51.2}{162.56}$

$P_1 = \frac{3901.44cm}{162.56}$

$P_1 = 24cm$

<em>Hence, the length of Phil's shadow is 24 cm</em>

6 0

2 years ago