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mamaluj [8]
3 years ago
7

an object which has a mass of 70 kg is sitting on a cliff 10 m high calculate the objects gravitational potential energy given g

= 1o/s^
Physics
1 answer:
Alex73 [517]3 years ago
5 0
GPE = mgh (for objects close to earth where g can be considered to be constant) Where m is the mass, g is the acceleration due to gravity (which the question has told us to assume is 10ms^-2), and h is the height of the object.

Substituting the values in:
GPE = 70*10*10 = 7000J
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Pls someone help me with this :(
RUDIKE [14]

4.0 is gonna be your answer






6 0
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To calculate the velocity of an object the of the position vs time graph should be calculated
frutty [35]
<span>The vertical axis represents the velocity of the object</span>
3 0
3 years ago
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Which of the following statements are true? Check all that apply.
lidiya [134]

We have 6 levels and we will verify which of them is true.

<em>A ) Electric charge is conserved </em>

According to the conservation of charge, an electric charge can neither be created nor be destroyed.

Therefore this statement is TRUE.

<em>B ) A positive charge and negative charge attract each other</em>

According to the properties of charges, the opposite charges attract each other and similar charges repel each other

Therefore this statement is  TRUE

<em>C) Two positive charges attract each other.</em>

Using the previous law, we can observe that this statement is false, because equal charges repel each other.

Therefore this statement is FALSE.

<em>D ) Two negative charges repel each other.</em>

Using the same principle as the two previous statements, two equal charges repel each other.

Therefore this statement is TRUE

<em>E) Electric charge is quantized.</em>

According to the quantization of charge, charges can take values only in integral multiples of a fundamental unit of charge.

Therefore this statement is TRUE.

<em>F) A neutral object contains no charge.</em>

A neutral object contains equal amount of negative and positive charge. Thus, in totality a neutral object contains no charge.

Therefore this statement is TRUE.

8 0
3 years ago
Certain rifles can fire a bullet with a speed of 950 m/s just as it leaves the muzzle (this speed is called the muzzle velocity)
TiliK225 [7]

Answer:

a) By v^2 = u^2 + 2as => a= 70291.70.

(b)By v = u + at => t= 1.58 ms.

(c)By v^2 = u^2 - 2gh => H = 46045.92 m.

Explanation:

a) By v^2 = u^2 + 2as

(950)^2 = 0 + 2 \times a \times 0.75\\a = 601666.67 m/s^2\\a/g = 688858.70/9.8 = 70291.70

(b)By v = u + at

950 = 0 + 601666.67 \times t\\t = 1.58 x 10^-3 sec = 1.58 ms

(c)By v^2 = u^2 - 2gh

0 = (950)^2 - 2 \times9.8 \times H\\H = 46045.92 m

4 0
3 years ago
A body is dropped from the roof of a 20 m high building by how much:
USPshnik [31]

Answer:

t = 2.01 s

Vf = 19.7 m/s

Explanation:

It's know through the International System that the earth's gravity is 9.8 m/s², then we have;

Data:

  • Height (h) = 20 m
  • Gravity (g) = 9.8 m/s²
  • Time (t) = ?
  • Final Velocity (Vf) = ?

==================================================================

Time

Use formula:

  • \boxed{t=\sqrt{\frac{2*h}{g}}}

Replace:

  • \boxed{t=\sqrt{\frac{2*20m}{9.8\frac{m}{s^{2}}}}}

Everything inside the root is solved first. So, we solve the multiplication of the numerator:

  • \boxed{t=\sqrt{\frac{40m}{9.8\frac{m}{s^{2}}}}}

It divides:

  • \boxed{t=\sqrt{4.08s}}

The square root is performed:

  • \boxed{t=2.01s}

==================================================================

Final Velocity

use formula:

  • Vf = g * t

Replace:

  • Vf = 9.8 m/s² * 2.01 s

Multiply:

  • Vf = 19.7 m/s

==================================================================

How long does it take to reach the ground?

Takes time to reach the ground in <u>2.01 seconds.</u>

How fast does it hit the ground?

Hits the ground with a speed of <u>19.7 meters per seconds.</u>

7 0
3 years ago
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