Runner 2 sees Runner 1 passing him with a velocity of 17 m/s west.
Answer:
Anyone can sit in a corner office and delegate tasks, but there is more to effective leadership than that. Effective leaders have major impacts on not only the team members they manage, but also their company as a whole. Employees who work under great leaders tend to be happier, more productive and more connected to their organization – and this has a ripple effect that reaches your business's bottom line
Explanation:
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<span>When you are setting up your budget, it is easier to start by setting your budgeting amounts based on the average of your last three months of spending. Many budgeting programs can import past transactions and help you come up with the estimates that you need for your budget. Then you can begin to make adjustments after you have those initial amounts.
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The two main goals are to spend less than you earn and to know where your money is going. Once you have a working budget you can work towards your other goals of saving money and getting out of debt. It is important to avoid theses common budgeting mistakes <span>when setting up your budget.
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Answer:
x = 0.396 m
Explanation:
The best way to solve this problem is to divide it into two parts: one for the clash of the putty with the block and another when the system (putty + block) compresses it is spring
Data the putty has a mass m1 and velocity vo1, the block has a mass m2
. t's start using the moment to find the system speed.
Let's form a system consisting of putty and block; For this system the forces during the crash are internal and the moment is preserved. Let's write the moment before the crash
p₀ = m1 v₀₁
Moment after shock
= (m1 + m2) 
p₀ =
m1 v₀₁ = (m1 + m2) 
= v₀₁ m1 / (m1 + m2)
= 4.4 600 / (600 + 500)
= 2.4 m / s
With this speed the putty + block system compresses the spring, let's use energy conservation for this second part, write the mechanical energy before and after compressing the spring
Before compressing the spring
Em₀ = K = ½ (m1 + m2)
²
After compressing the spring
= Ke = ½ k x²
As there is no rubbing the energy is conserved
Em₀ = 
½ (m1 + m2)
² = = ½ k x²
x =
√ (k / (m1 + m2))
x = 2.4 √ (11/3000)
x = 0.396 m
Answer:
also increase
Explanation:
If the mass increases so will the weight.