Answer:
9 ft*lb
Explanation:
super simple but you just have to understand that the integral is going with the curve
work = integral a to b of f(x)dx = integral 0 to 9 of 10/(1+x)^2dx = 9ft*lb
C metal. most metals are a conductor which an electric current is attracted to.
Answer:
The kinetic energy increases 4 times
Explanation:
Given,
The mass of the car, m = 1500 Kg
The speed of the car doubles from 50 Km/h to 100 Km/h
The kinetic energy at 50 Km/h
K.E = ½mv²
= ½ x 1500 x 50²
= 1875000 J
The kinetic energy of the car at 100 Km/h
K.E = ½mv²
= ½ x 1500 x 100²
= 7500000 J
Hence, the final K.E is 4 times the initial K.E
The field lines spread apart as we move away from the charge, and they point away from the charge
Explanation:
The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation

where
k is the Coulomb's constant
Q is the magnitude of the charge
r is the distance from the charge at which the field is calculated
There are two pieces of information given by the field lines shown in the graph:
- The spacing between the lines gives an indication of the strength of the field: the closer to each other they are, the stronger the field. In this case, as we move away from the charge, the spacing between the lines increases, and this means that the field becomes weaker (in fact, it follows an inverse square law,

- The direction of the lines gives the direction of the electric field, which points away from the central charge. This is because the direction of the electric field corresponds to the direction of the force that a positive test charge would feel when immersed in the electric field: in this case, if we place a positive test charge in this field, then it would get repelled away from the central charge (remember that the electric force between two positive charges is repulsive), and therefore, the direction of the electric field is away from the central charge.
Learn more about electric field:
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(a) The magnitude of the force that the magnetic field exerts on the loop is 0.042 N.
(b) The direction of the force that the magnetic field exerts on the loop will be out of the plane.
<h3>
Magnetic force exerted on the loop</h3>
F = BIL
where;
- I is current in the loop
- L is length of the loop
emf = BVb
where;
- b is breadth of the loop
- V is velocity
- B is magnetic field
emf = 2.6 x 3 x 0.018 = 0.1404 V
Current in the loop, I = emf/R = 0.1404/0.8 = 0.18 A
<h3>Magnetic force</h3>
F = BIL
where;
F = 2.6 x 0.18 x 0.09 = 0.042 N
<h3>Direction of the force</h3>
The direction of the force that the magnetic field exerts on the loop will be out of the plane.
Learn more about magnetic force here: brainly.com/question/13277365
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