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3 years ago

If a box has a length of 10.0 cm, a width of 20.0 cm, and a height of 5.00 cm, then what is its volume in m^3?

Physics

1 answer:

lesya692 [45]3 years ago

6 0

Explanation:

Solution,

Given:-

Length=10 cm
Width= 20 cm
Height= 5 cm
Volume =?

Now,

By using the formula of volume of a cuboid, we have

volume=length×width×height
volume=10 cm×20 cm×5 cm
volume=1000 cm³
volume= 1×10×10×10×10 cm³
volume=(1×10⁴) cm³

Hence, last option is the correct answer.

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What’s a good hypothesis and and experiment for water?

Lelu [443]

Answer: You could do something like, "how does water react to being mixed with baking soda"...or something along those lines

Explanation:

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3 years ago

The Heaviside function H is defined by H(t)={0 if t<0, 1 if t≥0 It is used in the study of electric circuits to represent the

Studentka2010 [4]

Answer:

$V(t)= 240V* H(t-5)$

Explanation:

The heaviside function is defined as:

$H(t) =1 \quad t\geq 0\\H(t) =0 \quad t$

so we see that the Heaviside function "switches on" when $t=0$ , and remains switched on when $t>0$

If we want our heaviside function to switch on when $t=5$ , we need the argument to the heaviside function to be 0 when $t=5$

Thus we define a function f:

$f(t) = H(t-5)$

The $-5$ term inside the heaviside function makes sure to displace the function 5 units to the right.

Now we just need to add a scale up factor of 240 V, because thats the voltage applied after the heaviside function switches on. ( $H(t-5) =1$ when $t\geq 5$ , so it becomes just a 1, which we can safely ignore.)

Therefore our final result is:

$V(t)= 240V* H(t-5)$

I have made a sketch for you, and added it as attachment.

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3 years ago

2. At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (nautical miles per hour; a n

AleksandrR [38]

Answer:

Explanation:

Let the reference origin be location of ship B in the beginning. We can then create the equation of motion for ship A and ship B in term of time t (hour):

A = 12 - 12t

B = 9t

Since the 2 ship motions are perpendicular with each other, we can calculate the distance between 2 ships in term of t

$d = \sqrt{A^2 + B^2} = \sqrt{(12 - 12t)^2 + (9t)^2}$

For the ships to sight each other, distance must be 5 or smaller

$d \leq 5$

$\sqrt{(12 - 12t)^2 + (9t)^2} \leq 5$

$(12 - 12t)^2 + (9t)^2 \leq 25$

$144t^2 - 288t + 144 + 81t^2 - 25 \leq 0$

$225t^2 - 288t + 119 \leq 0$

$(15t)^2 - (2*15*9.6)t + 9.6^2 + 26.84 \leq 0$

$(15t^2 - 9.6)^2 + 26.84 \leq 0$

Since $(15t^2 - 9.6)^2 \geq 0$ then

$(15t^2 - 9.6)^2 + 26.84 > 0$

So our equation has no solution, the answer is no, the 2 ships never sight each other.

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4 years ago

Four resistors , R1=12ohms, R2= 15 ohms , R3= 18 ohms and R4=10 ohms are connected to 6 v battery in series what is the total re

morpeh [17]

Answer:

55 ohms

Explanation:

if it was series circuit, then you just need to add all the resistances

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3 years ago

Which of the following best describes the domains of unmagnetized iron?

Scilla [17]

Magnetic domain is defined as a group of atoms with magnetic fields.

A piece of iron can only become a magnet when the magnetic domain aligns.

Since we have an unmagnetized piece of iron, this means that its domain is not aligned. However, this does not mean that the domain does not exist.

Based on the above, the best choice would be:
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Hope this helps :)

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3 years ago