This one is a piece 'o cake if you know the definition
of a horsepower, and impossible if you don't.

It is: 1 horsepower = 746 watts

Also, remember that 1 watt = 1 joule/second

Now: Work = (force) x (distance)

To move this box 2 meters,

   Work = (1,492 newtons) x (2 meters) = 2,984 joules

If you accomplished that feat in 1 second,
then you produced power of

   (2,984 / 1) (joule/second) = 2,984 watts .

   (2,984 watt) x (1 HP / 746 watt) = 4 horsepower .

That's the solution, applying bullet-proof math and physics to the
given data. But in the real world, I guarantee that you didn't do that.
______________________________________

By the way ... a comment regarding the terminology in the question:

The box doesn't "have a force" of 1,492 newtons. That's the force
with which you ... or a horse, or an ox ... pushed against the box
in order to move it.

(And, if I might observe, that force is about 336 pounds,
so my money would be on the horse or the ox.)

5 0

2 years ago

A runner taking part in the 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of

nlexa [21]

Answer:

$a_c=1.44\ m/s^2$

Explanation:

Centripetal Acceleration

It's the acceleration that an object has when traveling on a circular path to take into consideration the constant change of velocity it must have in order to keep going in the circular path.

Being v the tangent speed, and r the radius of curvature of the circle, then the centripetal acceleration is given by

$\displaystyle a_c=\frac{v^2}{r}$

We can compute the value of v by using the distance and the time taken to travel:

$\displaystyle v=\frac{x}{t}=\frac{200\ m}{26.4\ s}$

$v=7.58\ m/s$

Now we calculate the centripetal acceleration

$\displaystyle a_c=\frac{7.58^2}{40}=1.44\ m/s^2$

$\boxed{a_c=1.44\ m/s^2}$

4 0

3 years ago

A positive and a negative charge, each with a magnitude of 1.41 x 10^-5 C, are separated by a distance of 0.44 m. Find the force

vredina [299]

For this question, we use the Coulumb's law to calculate the force on each particles. In this law, force between point charges are said to be proportional to product of each charge and is indirectly proportional to the distance of both charges. We do as follows:

F= kq(1)q(2)/d^2
= (9x10^9).(1.41 x 10^-5 C).(-1.41 x 10^-5 C)/.44^2
 = 4.067 N

6 0

3 years ago

A VHF television station assigned to channel 4 transmits its signal using radio waves with a frequency of 66.0 MHz. Calculate th

soldi70 [24.7K]

Answer:

The wavelength is 4.55 m.

Explanation:

Given data

Frequency (ν): 66.0 MHz = 66.0 × 10⁶ Hz = 66.0 × 10⁶ s⁻¹

Speed of light (c): 3.00 × 10⁸ m/s

Wavelength (λ): To be found

We can determine the wavelength of the radio waves using the following expression.

c = λ × ν

λ = c / ν

λ = (3.00 × 10⁸ m/s)/66.0 × 10⁶ s⁻¹

λ = 4.55 m

6 0

2 years ago