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2 years ago

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josiah is taking his friends to the movies each ticket cost $10, and popcorn is $5 a bag. there is a 3$ service fee for the enti

re purchase he has 75$. If he buys 4 tickets, what is the maximum number of bags of popcorn he can buy A x+y=75 B10x+5Y+3<75 C10x+5y<75 D10x+5y+3>75

1 answer:

amid [387]2 years ago

8 0

Answer:

10x+5y+<=75

Step-by-step explanation:

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Dedra used coupons 6 times at the store last month.

AVprozaik [17]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

I NEED HELP PLEASE, THANKS! :)

Mashutka [201]

<h2> Option A is the right option.</h2>

please see the attached picture for full solution..

Hope it helps..

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4 0

2 years ago

jasmine and waldo went bowling if you took 12 points away from Waldo's score, jasmines score was 3 times that if the sum of thei

Mademuasel [1]

<u>Answer:</u> Jasmine's score is given by

$3(x-12)=3(99-12)=3\times 87=261$

And Waldo's score = 99

<u>Step-by-step explanation:</u>

Let Waldo's score be x

Let Jasmine's score be 3(x-12)

According to question,

$x+3(x-12)=360\\\\x+3x-36=360\\\\4x-36=360\\\\4x=360+36\\\\4x=396\\\\x=\frac{396}{4}\\\\x=99$

So,

Jasmine's score is given by

$3(x-12)=3(99-12)=3\times 87=261$

And Waldo's score = 99

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B%20%20%5Csqrt%7B3x%7D%20%7D%7B1%20%2B%20e%5E%7B2x%7D%20%7D%20" id="TexF

kumpel [21]

$~~~~~~~~y = \dfrac{\sqrt{3x}}{ 1+ e^{2x}}\\\\\\\implies \dfrac{dy}{dx} = \dfrac{d}{dx} \left( \dfrac{\sqrt{3x}}{1+ e^{2x}} \right)\\\\\\~~~~~~~~~~~~=\dfrac{(1 + e^{2x} ) \dfrac{d}{dx} \left(\sqrt{3x} \right) - \left(\sqrt{3x} \right)\dfrac{d}{dx}(1+e^{2x})}{\left( 1+ e^{2x} \right)^2}~~~~~~~~~~~~;[\text{Quotient rule}]\\\\\\~~~~~~~~~~~~=\dfrac{(1+e^{2x}) \cdot \dfrac{1}{2\sqrt{3x}} \cdot 3-\left(\sqrt{3x} \right) \cdot 2 e^{2x}}{(1 + e^{2x})^2}~~~~~~~~~~~~~~~~~~~~;[\text{Chain rule}]\\\\\\$

$=\dfrac{\dfrac{\sqrt 3 (1 + e^{2x})}{2\sqrt x} -2e^{2x} \sqrt{3x}}{(1+e^{2x})^2}\\\\\\=\dfrac{\tfrac{\sqrt 3(1 +e^{2x}) - 4x\sqrt 3 e^{2x}}{2\sqrt x}}{(1+e^{2x})^2}\\\\\\=\dfrac{\sqrt 3(1+e^{2x} -4xe^{2x})}{2\sqrt x(1 +e^{2x})^2}$

7 0

1 year ago

A wire is first bent into the shape of a square. Each side of the square is 6cm long. Then the wire is unbent and reshaped into

MaRussiya [10]

Hi there!

Assuming a perfect square: we know there are 4 sides in a square, and all of them have equal length. This means that every side of the square is 6 cm, and with 4 sides, that would make an overall length / perimeter of 6 + 6 + 6 + 6, or 6*4, which would equal 24 cm. This means that our wire must be 24 cm long.

Now, for the rectangle. We know with rectangles that they also have 4 sides, and in pairs of 2 in terms of length (2 of the sides have the same length, and the other two have the same length). This means we know there are 2 sides that are 9 cm, which would mean 18 cm in total. This is the total amount of wire taken up by the length, but we are looking for the width. Thus, we can see how much wire is leftover not taken up by the length by subtracting 18 from 24:

24-18=6

Now, we see that the two sides that make up the width are 6 cm long. As those two sides are equal length, we can divide 6 cm into two equal parts to see the width.

6/2 = 3 cm.

Thus, the width of the rectangle is 3 cm.

Hope this helps!

4 0

2 years ago