Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
8-3n
The way you know is 8 is the hidden word....
in there and it say 3 times nathans...
So you will take n and times it bye 3..
by doing 3n so 8-3n is your anwser...
<h2>Pwease Mark me Brainliest TY OwO</h2>
0.92 , 0.479 , 0.387 , 0.2
[See the last first digit after the decimal. I chose 0.92 since 9 is the greater than 2,3 and 4]
Answer:
Step-by-step explanation:
<u>Step 1: Distribute</u>
<u />
Answer:
To find the area of a rectangle, multiple the width by the length.
(And simply the fractions for a simpler equation)
For piece A:
The length 1 and 3/5 can be turned into an improper fraction by multiplying 1 by the denominator (5) and adding it to the numerator (3). 1 and 3/5 = 8/5
(3/4) • (8/5) = area
Multiple the numerators with each other and the denominators with each other (3 times 8 = 24) (4 times 5 = 20)
The area of piece A is 24/20
If you do the same for piece B:
(2/5) • (21/8) = area
The answer is 42/40
