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Trava [24]
4 years ago
14

How to find speed of an object

Physics
1 answer:
____ [38]4 years ago
4 0
Speed= distance divided by time
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3 years ago
Which type of energy increases when an object’s atoms move faster? A.nuclear B.mechanical C.chemical D.thermal
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When an object's atoms move faster, its thermal energy increases and the object becomes warmer.
4 0
4 years ago
Read 2 more answers
Calculate the acceleration of a bottle rocket that is traveling at a speed of 74 m/s, and then descends at a speed of 89 m/s. It
Harlamova29_29 [7]

Answer:Falling objects form an interesting class of motion problems. For example, we can estimate the depth of a vertical mine shaft by dropping a rock into it and listening for the rock to hit the bottom. By applying the kinematics developed so far to falling objects, we can examine some interesting situations and learn much about gravity in the process.

Explanation:

5 0
3 years ago
A person tosses a ball from the ground up into the air at an initial speed of 10 m/sec and an initial angle of 43° off the groun
Artemon [7]
<h2>Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s</h2>

Explanation:

In horizontal direction there is acceleration or deceleration for a ball tossed upward at an initial angle of 43° off the ground.

So the horizontal component of velocity always remains the same.

Horizontal component of velocity is the cosine component of velocity.

Initial velocity, u = 10 m/s

Angle, θ = 43°

Horizontal component of velocity = u cosθ

Horizontal component of velocity = 10 cos43

Horizontal component of velocity = 7.31 m/s

Since the horizontal velocity is unaffected, we have

     Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s

5 0
4 years ago
A train is moving along a track with constant speed v1 relative to the ground. A person on the train holds a ball of mass m and
scoundrel [369]

Answer:

(a)0.5m(2v1v2+v2^{2})\\(b)0.5m(v2^{2}-v1^{2})\\(c)0.5m(2v1v2+v2^{2})\\(d)0.5m(v2^{2}-v1^{2})

Explanation:

velocity of ball in train reference = v2

velocity of ball in earth reference = v1+v2

(a)

Kinetic energy is given by 0.5mv^{2} where m and v are the mass and velocity of object respectively.

Change in kinetic energy is given by subtracting initial kinetic energy from the final kinetic energy. In this case

Initial kinetic energy= 0.5mv1^{2}

Final kinetic energy= 0.5m (v1+v2)^{2}=0.5m(v1^{2}+2v1v2+v2^{2})

Change in kinetic energy=0.5m (v1+v2)^{2}-0.5mv1^{2}=0.5m((v1+v2)^{2})-v1^{2}=0.5m(2v1v2+v2^{2}

(b)

Change in velocity in train reference will be

Initial kinetic energy= 0.5mv1^{2}

Final kinetic energy= 0.5mv2^{2}

Change in kinetic energy=0.5m(v2^{2}-v1^{2})

(c)

Work done, W = change in kinetic energy=0.5m (v1+v2)^{2}-0.5mv1^{2}=0.5m((v1+v2)^{2})-v1^{2}=0.5m(2v1v2+v2^{2}

(d)

Work done, W = change in kinetic energy=0.5m(v2^{2}-v1^{2})

4 0
3 years ago
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