Answer:
It's impossible for an ideal heat engine to have non-zero power.
Explanation:
Option A is incomplete and so it's possible.
Option B is possible
Option D is related to the first lae and has nothing to do with the second law.
Hence, the correct option is C.
The ideal engine follows a reversible cycle albeit an infinitely slow one. If the work is being done at this infinitely slow rate, the power of such an engine is zero.
We can also stat the second law of thermodynamics in this manner;
It is impossible to construct a cyclical heat engine whose sole effect is the continuous transfer of heat energy from a colder object to a hotter one.
This statement is known as second form or Clausius statement of the second law.
Thus, it is possible to construct a machine in which a heat flow from a colder to a hotter object is accompanied by another process, such as work input.
You clearly identified the pole you're talking about as the
"north-seeking" pole. Assuming your integrity and sincerity,
we would then naturally expect that pole to seek north, and
point to Earth's north magnetic pole.
I'm confident in this answer also because I have several of
these devices hanging from the ceiling of my office, and I can
attest to the fact that on most clear days, they do in fact point
toward Earth's north magnetic pole.
Heat will be produced because of the friction from the tires
A probability contour represents a bounded, finite volume about a nucleus in which there is a substantial probability of finding the electron is TRUE.
The rectangular of the wave characteristic, ψ2 , represents the opportunity of locating an electron in a given vicinity within the atom. probability finding electron at nucleus is zero.
An orbital is a mathematical feature that has a fee at all points in space. The magnitude squared of that fee is the chance according to volume of locating an electron in that volume of area.
The probability of locating electron in nodes is 0, but there are electron densities on all round nodes. The node is a point or a floor (relying at the type of node) so the volume of the vicinity wherein ψ=zero is zero. we want to position V=zero and we get P=zero so the chance of finding the electron on the node is zero.
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Answer:
a. 11.5kv/m
b.102nC/m^2
c.3.363pF
d. 77.3pC
Explanation:
Data given

to calculate the electric field, we use the equation below
V=Ed
where v=voltage, d= distance and E=electric field.
Hence we have

b.the expression for the charge density is expressed as
σ=ξE
where ξ is the permitivity of air with a value of 8.85*10^-12C^2/N.m^2
If we insert the values we have

c.
from the expression for the capacitance

if we substitute values we arrive at

d. To calculate the charge on each plate, we use the formula below
