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xxTIMURxx [149]
3 years ago
12

If an object is pushed to the right by a force of 7N and pushed to the left by a force of 7N ,what is the resultant force on the

object?
Physics
2 answers:
Lunna [17]3 years ago
8 0
7-7 = 0 N
The resultant (or net) force is 0 N
Ivahew [28]3 years ago
6 0
Pushed to the right = 7N
Pushed to the left = -7N
(As conventionally right to left is + and left to right is - )

Thus when we add the total forces:-
7N + (-7N) = 0

Hence the resultant or net force acting on the object is 0N
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If only 10 pounds is required to lift a 500-lb block, how much chain must be played out to lift the engine 3.0 inches?
adelina 88 [10]

Answer:

150 inches (12.5 ft)

Explanation:

The work done to lift the 500 pound block 3 inches should be the same as that to lift the 10 pond object a given distance.

The following is the equation one needs to solve:

10 \,lb\,* \,x\,=\,500\,lb\,*\,3\,in\\10 \,lb\,* \,x\,=\,1500\,lb\,in\\

therefore solving for the distance "x" gives as the answer (in inches):

10 \,lb\,* \,x\,=\,1500\,lb\,in\\x\,=\,\frac{1500\,lb\,in}{10\,lb} \\\\x\,=150\,in

which can also be given in feet as: 12.5 ft

3 0
3 years ago
A light string is wrapped around the edge of the smaller disk, and a 1.50 kg block is suspended from the free end of the string.
LenaWriter [7]

Answer: 7.41 m/s

Explanation: By using the law of of energy, kinetic energy of the brick as it falls equals the potential energy before falling.

Kinetic energy = mv²/2, potential energy = mgh

mv²/2 = mgh

v²/2 = gh

v² = 2gh

v = √2gh

Where g = 9.8 m/s², h = 2.80m

v = √2×9.8×2.8 = 7.41 m/s

7 0
3 years ago
Since the moon has less mass than the earth what happens to objects on the moon
postnew [5]
When you drop an object on the moon, it falls to the ground.
But it only falls about 1/6 as fast as it falls on Earth.
4 0
3 years ago
A force of 250 N is applied to a hydraulic jack piston that is 0.02 m in diameter. If the piston that supports the load has a di
Vikentia [17]

Answer:

option B

Explanation:

given,

Force exerted by the hydraulic jack piston = F₁ = 250 N

diameter of piston, d₁ = 0.02 m

                                r₁ = 0.01 m

diameter of second piston,  d₂ = 0.15 m

                                r₂ = 0.075 m

mass of the jack to lift = ?

now,

    \dfrac{F_1}{A_1} =\dfrac{F_2}{A_2}

    \dfrac{250}{\pi r_1^2} =\dfrac{F_2}{\pi r_2^2}

    \dfrac{250}{0.01^2} =\dfrac{F_2}{0.075^2}

    F_2= \dfrac{250}{0.01^2}\times {0.075^2}

               F₂ = 14062.5 N

F = m g

m = \dfrac{F}{g}

m = \dfrac{14062.5}{9.8}

m = 1435 Kg

hence, the correct answer is option B

5 0
3 years ago
Sounds waves are an example of which type of wave? Longitudinal Transverse O Electromagnetic​
erastova [34]

Answer:

Happy now?

Explanation:

Correct answer:

Sound waves are longitudinal waves, meaning that the waves propagate by compression and rarefaction of their medium. They are termed longitudinal waves because the particles in the medium through which the wave travels (air molecules in our case) oscillate parallel to the direction of motion.

8 0
2 years ago
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