The distance between any point (x0,y0) on the parabola and the focus (m,n) is the same as the distance between (x0,y0) and the directrix line ax+by+c. The distance between (x0,y0) and focus (a,b) is \sqrt((x-m)^2+(y-n)^2). The distance between (x0,y0) and ax+by+c is |ax0+by0+c|/\sqrt(m^2+n^2). Equalize these two expressions.
Answer:
1 yard by 9 yards
2 yards by 8 yards
3 yards by 7 yards
4 yards by 6 yards
Step-by-step explanation:
the perimeter of the rectangular yard needs to be 20 yards
Perimeter of a rectangle = 2 x ( length + width)
20 = 2 x ( length + width)
( length + width) = 20 /2
( length + width) = 10
The sum of the length and width should equal 10
Possible dimensions that would equal 10 are :
1 yard by 9 yards
2 yards by 8 yards
3 yards by 7 yards
4 yards by 6 yards
Solution is supposed to be as follows
<span>u+<span>2 / 3</span><span> u<span>^3/2</span></span>
=r+<span>2 / 3</span><span> r^<span>3/2</span></span> + <span>c</span></span>
Answer:
12144.
Step-by-step explanation:
(self-explanatory)
I hope this helped, have a nice day.
