A right triangle has a leg b of length 7 and a hypotenuse of length 11 what is the length of the other leg a?
1 answer:
A^2 + b^2 = c^2
a^2 + 7^2 = 11^2
49= 121
121 - 49 = 72
Square root(72) = 8.49
or you can just keep the square root symbol with 72 under it
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10P8 = 10!/(10 - 8)! = 10!/2! = 1,814,400
Answer:
x= -3
Step-by-step explanation:
Solve the rational equation by combining expressions and isolating the variable x.
The lenght would be 12*4 is 48
