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Svetradugi [14.3K]
3 years ago
5

On which factor does the inertia of rest depends​

Physics
1 answer:
daser333 [38]3 years ago
8 0

Answer:

Inertia depends upon the force applied .

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When a skateboarder rides down a hill, the normal force exerted on the skater by<br> the hill is
Luda [366]

Newton's second law allows us to find that the correct answer is:

  • Less than weight of the skater

Newton's second law states that the net force and is propositional to the mass and acceleration of the body

For these problems it is essential to set a reference system, with respect to which to carry out the measurements, in this case we set a coordinate system with the x axis parallel to the plane and positive in the direction of movement and the y axis perpendicular to the plane.

In the attachment we can see a free-body diagram of the problem, let's work each axis separately

x-axis

         Wₓ -fr = m a

y-axis

         N - W_y = 0

         N = W_y

Where Wₓ and W_y are the components of the weight, fr the friction force that opposes the movement, m the mass and the acceleration of the body

let's use trigonometry to find the components of the weight

        cos θ = \frac{W_y}{W}

        sin θ = \frac{W_x}{W}

         W_y = W cos θ

         Wₓ = W sin θ

we substitute

          N = mg cos θ

From this equation we can see that the normal is less than the weight of the body.

In conclusion using Newton's second law we find that the correct answer is:

  • Less than th weight of the skater

 

Learn more about Newton's second law here:

brainly.com/question/13685393

3 0
2 years ago
(a) When the terminals of a 100-V battery are connected to two parallel plates 1 cm apart, what is the electrical field in the r
DaniilM [7]

Answer:

The electrical field in the region between the plates is 10,000 V/m.

Explanation:

Given;

potential difference between the two parallel plates, V = 100 V

distance between the two parallel plates, d = 1 cm = 0.01 m

The electrical field in the region between the plates is given as;

E = V / d

where;

E is the electrical field in the region between the plates

E = (100) / (0.01)

E = 10,000 V/m

Therefore, the electrical field in the region between the plates is 10,000 V/m.

3 0
3 years ago
Which statement best describes how reproduction leads to natural selection in a population?
lorasvet [3.4K]

Organisms overproduce offspring, so only some survive and pass on their traits.

Natural selection is the fitting of a population to its environment.

Explanation:

Most organisms produce more than two or more offspring in their lifetime. Therefore the subsequent generations ideally have more individuals than the previous. However, naturally, the population size does not grow indefinitely. This is because some individuals do not survive to pass their genes to the next generation. Natural selection chooses the best fit individuals to habitat, and these live long enough to pass their traits to the next generation. Natural selection powers the evolution of a population even as environment changes  

Learn More:

For more on natural selection check out;

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#LearnWithBrainly

8 0
3 years ago
Read 2 more answers
A hiker, caught in a rainstorm might absorb 1 liter of water in her clothing. if it is windy so that this amount of water is eva
NeTakaya

Water evaporates at 100⁰C

So change in temperature = 100-20 = 80⁰C

Amount of water to be evaporated = 1 liter = 1L*1kg/liter = 1 kg

Specific heat of water is 1 calorie/gram ⁰C = 4.186 joule/gram =4186 J/kg

So heat required E = mcΔT = 1 * 4186 *80= 334880 J =334.88 kJ

So amount of heat require to evaporate water = 334.88 kJ

4 0
3 years ago
A gymnast does a one-arm handstand. The humerus, which is the upper arm bone between the elbow and the shoulder joint, may be ap
igor_vitrenko [27]

Answer:

                  = 5.241 \times 10^{-5} m

Explanation:

Given:

 Length of cylinder is, L = 0.27 m

Outer radius of cylinder is, r_out = 1.12×10^{-2} m

Inner radius of cylinder is, r_in = 3.9×10^{-3} m

Mass of person, m = 60 kg

 Young's modulus , Y = 9.4×10^9 N/m2

(a)

     Compressional strain of humerous is,

Strain = \frac{Stress}{Young's\ modulus}

     \frac{\Delta L}{L_0}   = \frac{\frac{F}{A}}{Y}

                  = \frac{(mg)}{\pi(r_out^2 - r_in^2  )Y}

                  = \frac{(60 kg)(9.8 m/s2 )}{(\pi)[( 1.12\times 10^{-2})^2 - (3.9\times 10^{-3} m)^2] (9.4\times 10^9 N/m2 )}[tex]                   [tex]= 1.80\times 10^{-4} m

(b)  Let assume that humerous is compressed by ΔL

       Since,   strain = ΔL/L0

      (1.80 \times 10^{-4} m) = ΔL / 0.29 m

     Thus,

           ΔL = (4.56 \times 10^{-4} m)(0.29 m)

                  = 5.241 \times 10^{-5} m

7 0
3 years ago
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