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muminat
3 years ago
15

Determine the linear velocity of an object with an angular velocity of 5.9 radians per second at a distance of 12 centimeters fr

om the center. use . round the answer to the nearest tenth.
Physics
1 answer:
Andre45 [30]3 years ago
7 0
The linear velocity of a rotating object is the product of the angular velocity and the radius of the circular motion. Angular velocity is the rate of the change of angular displacement of a body that is in a circular motion. It is a vector quantity so it consists of a magnitude and direction. From the problem, the angular velocity is 5.9 rad per second and the radius is given as 12 centimeters. We calculate as follows:

Linear velocity = angular velocity (radius)
Linear velocity = 5.9 (12 ) = 70.8 cm / s

The linear velocity of the body in motion is 70.8 centimeters per second or 0.708 meters per second.
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Joe and Max shake hands and say goodbye. Joe walks east 0.40 km to a coffee shop, and Max flags a cab and rides north 3.65 km to
katen-ka-za [31]

Answer:

3.67 km

Explanation:

Joe distance towards coffee shop is,

OB=0.40 km

And the Max distance towards bookstore is,

OA=3.65 km

Now the distance between the Joy and Max will be,

By applying pythagorus theorem,

AB=\sqrt{OB^{2}+OA^{2}}

Substitute 0.40 km for OB and 3.65 km for OA in the above equation.

AB=\sqrt{0.40^{2}+3.65^{2}}\\AB=\sqrt{13.4825} \\AB=3.67 km

Therefore the distance between there destination is 3.67 km.

6 0
3 years ago
The current in a wire varies with time according to the relationship 1=55A−(0.65A/s2)t2. (a) How many coulombs of charge pass a
mario62 [17]

Answer:

(A) Q = 321.1C (B) I = 42.8A

Explanation:

(a)Given I = 55A−(0.65A/s2)t²

I = dQ/dt

dQ = I×dt

To get an expression for Q we integrate with respect to t.

So Q = ∫I×dt =∫[55−(0.65)t²]dt

Q = [55t – 0.65/3×t³]

Q between t=0 and t= 7.5s

Q = [55×(7.5 – 0) – 0.65/3(7.5³– 0³)]

Q = 321.1C

(b) For a constant current I in the same time interval

I = Q/t = 321.1/7.5 = 42.8A.

3 0
3 years ago
Read 2 more answers
What TWO things affect the gravitational force acting on an object?
ohaa [14]
The strength of the gravitational forces between two masses depends on

--  the product of the masses,

-- the distance between their centers of mass.
3 0
3 years ago
Read 2 more answers
It's for #8....I know the answer is 293.2 ft I just don't know how to get it
Oksi-84 [34.3K]
Kinectic Energy=1/2(mass)(velocity)^2 so 1.2=1/2(.0012)(position/2) so it travels 4000 m. Not sure how it is 293.2 ft
7 0
3 years ago
A fish-tank heater is rated at 96 W when connected to 120 V. The heating element is a coil of Nichrome wire. When uncoiled, the
nexus9112 [7]

Answer:

0.232 mm.

Explanation:

Power, P = 96 W

Voltage, V = 120 V

Length of wire, l = 4.2 m

Let r be the radius of the wire.

Resistivity of nichrome, ρ = 1.5 x 10^-6 ohm metre

P = V^2 / R

R = 120 x 120 / 96 = 150 ohm

R = \rho \frac{l}{A}=\rho \frac{l}{\pi r^{2}}

r^2= \rho \frac{l}{\pi \times R}

r^2= \1.5\times10^{-6} \frac{4.2}{3.14 \times 150}

r = 1.16 x 10^-4 m

Diameter = 2 x r = 2 x 1.16 x 10^-4 = 2.32 x 10^-4 m = 0.232 mm

Thus, the diameter of the wire is 0.232 mm.

3 0
3 years ago
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