Label the part that make up the human heart. Drag the item on the left to the correct location on the right.
2 answers:
Answer:
Attached is the picture with the answers
Explanation:
I will describe the parts of the heart in the picture starting on the left side of the image, up-down, then right side, up-down.
C. Right Atrium - Is one of the chambers in the heart where blood enters the ventricles. It's located in the upper right part and it receives blood from the venae cavae (deoxygenated blood)
F. Right Ventricle - Is one of the two large chambers located in the right lower part of the heart. It receives blood from the right atrium and pumps it to the lungs.
A. Aorta - It's the biggest and principal artery in the body. It comes out of the left ventricle and goes to the lower abdomen, where it splits into 2 smaller arteries, distributing oxygenated blood to the body.
E. Pulmonary artery - This artery, part of pulmonary circulation, takes deoxygenated blood from the right part of the heart into the lungs.
D. Left atrium - Is one of the chambers in the heart where blood enters the ventricles. It's located in the upper left part and it receives blood from the lungs (pulmonary circulation)
B. Left ventricle - Is one of the two large chambers located in the left lower part of the heart. It receives blood from the left atrium and pumps oxygenated blood through the aorta.
You might be interested in
The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.
<h3>What is Columb's law?</h3>The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.
They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.
The given data in the problem is;
q₁ is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C
F is the repulsive force = 36 mN =36 ×10⁶ N
d is the distance = 0.70 m
The Coulomb force is found as;
Hence, the magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C.
To learn more about Coulomb's law, refer to the link;
#SPJ2