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2 years ago

Label the part that make up the human heart. Drag the item on the left to the correct location on the right.

Physics

2 answers:

pantera1 [17]2 years ago

5 0

hey there! ;D

A) aorta - goes on the top right

E) pulmonary artery - goes below aorta

D) left atrium - goes below pulmonary artery

B) left ventricle - goes below left atrium

C) right atrium - goes on top left

F) right ventricle - goes below right atrium

hope this helps!

have an awesome day ;)

EleoNora [17]2 years ago

3 0

Answer:

Attached is the picture with the answers

Explanation:

I will describe the parts of the heart in the picture starting on the left side of the image, up-down, then right side, up-down.

C. Right Atrium - Is one of the chambers in the heart where blood enters the ventricles. It's located in the upper right part and it receives blood from the venae cavae (deoxygenated blood)

F. Right Ventricle - Is one of the two large chambers located in the right lower part of the heart. It receives blood from the right atrium and pumps it to the lungs.

A. Aorta - It's the biggest and principal artery in the body. It comes out of the left ventricle and goes to the lower abdomen, where it splits into 2 smaller arteries, distributing oxygenated blood to the body.

E. Pulmonary artery - This artery, part of pulmonary circulation, takes deoxygenated blood from the right part of the heart into the lungs.

D. Left atrium - Is one of the chambers in the heart where blood enters the ventricles. It's located in the upper left part and it receives blood from the lungs (pulmonary circulation)

B. Left ventricle - Is one of the two large chambers located in the left lower part of the heart. It receives blood from the left atrium and pumps oxygenated blood through the aorta.

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Answer:

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3 years ago

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BRAINLIEST WELL BE AWARDED. what is an alloy?

DedPeter [7]

Answer:

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Explanation:

Alloys are usually produced by melting the mixture of ingredients. The value of alloys was discovered in very ancient times; brass (copper and zinc) and bronze (copper and tin) were especially important. Today, the most important are the alloy steels, broadly defined as steels containing significant amounts of elements other than iron and carbon. The principal alloying elements for steel are chromium, nickel, manganese, molybdenum, silicon, tungsten, vanadium, and boron have a wide range of special properties, such as hardness, toughness, corrosion resistance, magnetizability, and ductility. Nonferrous alloys, mainly copper–nickel, bronze, and aluminum alloys, are much used in coinage. The distinction between an alloying metal and an impurity is sometimes subtle; in aluminum, for example, silicon may be considered an impurity or a valuable component, depending on the application, because silicon adds strength though it reduces corrosion resistance.

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2 years ago

A moving car skids to a stop with the wheels locked across a level roadway. Of the forces listed, identify which act on the car.

Vesnalui [34]

Answer:

Normal, Gravity, Friction, and Air Resistance.

Explanation:

When a moving car skid to stop and its wheels are locked across, then the following forces will be applied on the car:

Normal force: It will act counter to gravity that pushes an object against a surface and acts perpendicular to the contact surface.

Gravity: Gravity force acts in each and every object having mass and it can not be avoidable. So, the gravity force will also apply to the car and attract it to the earth's surface.

Friction: Friction is a force that acts opposite to the motion and stops or slows motion. Friction will be applied to the car that will oppose the motion of the car and stop it.

Air resistance: air resistance is defined as the forces exerted by air that acts opposite to the relative motion of an object. Air resistance will also be applied to the car when it will skid to stop as we are always surrounded by the air.

Hence, the correct answers are "Normal, Gravity, Friction, and Air Resistance."

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3 years ago

A satellite is in a circular orbit 21000 km above the Earth’s surface; i.e., it moves on a circular path under the influence of

mina [271]

Answer:

(orbital speed of the satellite) V₀ = 3.818 km

Time (t) = 4.5 × 10⁴s

Explanation:

Given that:

The radius of the Earth is 6.37 × 10⁶ m; &

the acceleration of gravity at the satellite’s altitude is 0.532655 m/s

We can calculate the orbital speed of the satellite by using the formula:

Orbital Speed (V₀) = √(r × g)

radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m

= (2.1 × 10⁷ + 6.37 × 10⁶) m

= 27370000

= 2.737 × 10⁷m

Orbital Speed (V₀) = √(r × g)

Orbital Speed (V₀) = √(2.737 × 10⁷ × 0.532655 )

= 3818.215

= 3.818 × 10³

= 3.818 Km

To find the time it takes to complete one orbit around the Earth; we use the formula:

Time (t) = 2 π × $\frac{r}{V_o}$

= 2 × 3.14 × $\frac{2.737*10^7}{3.818*10^3}$

= 45019.28

= 4.5 × 10 ⁴ s

6 0

3 years ago

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz. Find the possible range of wavelengths in ai

taurus [48]

Answer:

The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

Explanation:

Given that,

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.

The speed of sound in air is 343 m/s.

To find,

The wavelength range for the corresponding frequency.

Solution,

The speed of sound is given by the following relation as :

$v=f_1\lambda_1$

Wavelength for f = 45 Hz is,

$\lambda_1=\dfrac{v}{f_1}$

$\lambda_1=\dfrac{343}{45}=7.62\ m$

Wavelength for f = 375 Hz is,

$\lambda_2=\dfrac{v}{f_2}$

$\lambda_2=\dfrac{343}{375}=0.914\ m/s$

So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

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3 years ago