Their proton and electron numbers are same
Answer:
2.893 x 10⁻³ mol NaOH
[HCOOH] = 0.5786 mol/L
Explanation:
The balanced reaction equation is:
HCOOH + NaOH ⇒ NaHCOO + H₂O
At the endpoint in the titration, the amount of base added is just enough to react with all the formic acid present. So first we will calculate the moles of base added and use the molar ratio from the reaction equation to find the moles of formic acid that must have been present. Then we can find the concentration of formic acid.
The moles of base added is calculated as follows:
n = CV = (0.1088 mol/L)(26.59 mL) = 2.892992 mmol NaOH
Extra significant figures are kept to avoid round-off errors.
Now we relate the amount of NaOH to the amount of HCOOH through the molar ratio of 1:1.
(2.892992 mmol NaOH)(1 HCOOH/1 NaOH) = 2.892992 mmol HCOOH
The concentration of HCOOH to the correct number of significant figures is then calculated as follows:
C = n/V = (2.892992 mmol) / (5.00 mL) = 0.5786 mol/L
The question also asks to calculate the moles of base, so we convert millimoles to moles:
(2.892992 mmol NaOH)(1 mol/1000 mmol) = 2.893 x 10⁻³ mol NaOH
They are colourless solids (salts) that do not conduct electricity when solid, but conduct electricity in aqueous solution as the ions (that carry charge) are free to move.
They have a high melting point due to the strong electrostatic forces of attraction between oppositely charged ions
Best regards
Answer:
2H2S + 3O2 → 2SO2 + 2H2O
V(O2) = 48.4 L
p = 105 kPa = 1.036 atm
T = 190 + 273 = 463 K
Ideal gas law:
pV = nRT
n = \frac{pV}{RT}n=
RT
pV
R = 0.08206 L×atm/mol×K
n(O2) = \frac{1.036 \times 48.4}{0.08206 \times 463}=1.319 \; mol=
0.08206×463
1.036×48.4
=1.319mol
According to the reaction:
n(H2S) = \frac{2}{3}
3
2
n(O2) = \frac{2}{3} \times 1.319 = 0.8798 \;mol
3
2
×1.319=0.8798mol
V = \frac{nRT}{p} \\ V(H_2S) = \frac{0.8798 \times 0.08206 \times 463}{1.036}=32.26 \;LV=
p
nRT
V(H
2
S)=
1.036
0.8798×0.08206×463
=32.26L
Answer: 32.26 L
Explanation:
The inverse proportion is PV = k
We can write the equation as <em>P</em> = k/<em>V</em> or <em>P</em> ∝ 1/<em>V</em>. Thus, <em>P</em> and <em>V</em> are <em>inversely related</em>.
We can rewrite <em>V</em>= T/k as <em>V</em> = k<em>T</em> or <em>V</em> ∝ <em>T</em>. Thus,<em> V</em> is <em>directly proportiona</em>l to <em>T</em>
.
<em>F</em> = -k<em>x</em>² is <em>neither a direct nor an invers</em>e relation.
<em>y</em> = k<em>x</em> – 8 is a linear relation, but it is <em>not a direct proportion</em> because of the “-8” term.
