Answer:
Mass of KNO3 in the original mix is 146.954 g
Explanation:
mass of
in original 254.5 mixture.
moles of 
moles of
= 0.2926 mol of BaSO4
Therefore,
0.2926 mol of BaCl2,
mass of 
= 60.92 g
the AgCl moles 

= 1.3891 mol of AgCl
note that, the Cl- derive from both,
so
mole of Cl- f NaCl
mol of Cl-
mol of NaCl = 0.8039 moles

then
KNO3 mass = 254.5 - 60.92-46.626 = 146.954 g of KNO_3
Mass of KNO3 in the original mix is 146.954 g
Answer:
the answer is "I HOPE IT HELPS"
|F| = 112 - 67 = 45 N
F = 45 N ( to the left)
Explanation:
The given data is as follows.
Air is at
and 14.6 psia.
= 0.00015 ft, Flow rate, (Q) = 48000 
(a) Formula to calculate hydraulic radius
is as follows.

= 
=
ft
Formula for equivalent diameter is as follows.

=
=
ft
(b) Formula for velocity floe is as follows.
Q = VA
V = 
=
ft/min
= 24000 ft/min
(c) Formula to calculate Reynold's number is as follows.
= 
=
(as
and
= 0.0443 lb/ft. hr)
= 53742.66 hr/min
As 1 hr = 10 min. So, 
= 3224559.6
(d) Formula to calculate pressure drop
is as follows.

Putting the given values into the above formula as follows.

= 
= 6.238 
Answer:
1. No
2. No
3. Yes
4. No
5. Yes
6. No
Explanation:
Use the reactivity series. If the element is above it, it is more reactive. More reactive elements can displace less reactive elements from their compounds.