An object floats in a beaker as shown. when it was put into the beaker, it displaced an amount of water into the graduated cylin
1 answer:
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Answer:
4347.8 m/s
Explanation:
It is given that the radius of the circular path traversed by proton and electron is same. Also, we know that magnitude of charge on an electron and proton is same. Magnetic field strength is same for both.
Take the ratio:
Answer:
The speed and direction of the two players immediately after the tackle are 3.3 m/s and 53.4° South of West
Explanation:
given information:
mass of fullback, = 92 kg
speed of full back, = 5.8 to south
mass of lineman, =110 kg
speed of lineman, = 3.6
according to conservation energy,
assume that the collision is perfectly inelastic, thus
initial momentum = final momentum
=
'
m₁v₁ = (m₁+m₂)'
' = m₁v₁/(m₁+m₂)
= (92) (5.8)/(92+110)
= 2.64 m/s
=
'
m₂v₂ = (m₁+m₂)'
' = m₁v₁/(m₁+m₂)
= (110) (3.6)/(92+110)
= 1.96 m/s
thus,
' = √
'²+
'²
= 3.3 m/s
then, the direction of the two players is
θ = 90 - tan⁻¹('/
')
= 90 - tan⁻¹(1.96/2.64)
= 53.4° South of West