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Ivahew [28]
3 years ago
8

Consider the reaction 2 S + 3 O2 → 2 SO3 , which has a 75.1% yield. How much O2 is consumed if 583 g of SO3 are produced?

Chemistry
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

A/1.      10.9 mol O2

Explanation:

583 g x 1 mol SO3 x 3 mol O2 /

      80.057 g mol SO3 x 2 mol SO3

- You just need to find molar mass of SO3, which is 80.057 g.

- Everything else came from formula. Further explanation...

- Always start with what they give, such as 583 g. Then find 1 mol of what is being produced, in this it is SO3. We already found this because we did molar mass above. Next. find how many moles of what they want, which is O2. Look in equation and you can see 3 mol in from of O2. Next, do the same for SO3 and you can find 3 mol in front of that. Lastly, just do the math.

- If you need a further explanation or more help on any problems I would be happy to help, just let me know.

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Balance the chemical equation got the reaction of benzene and hydrogen to form cyclohexane
lozanna [386]
C₆H₆  +  3H₂  →  C₆H₁₂

Benzene + 3 molecules of hydrogen = cyclohexane

So essentially what happens is that benzene contains three double bonds and when reacted with hydrogen then these three double bonds can be broken and the hydrogen bond to the tetravalent carbon to restore its for bonds forming cyclohexane
4 0
3 years ago
Please Help!
eduard
Well they are different widths and and sizes shapes, and so they are  different because of that.
4 0
4 years ago
Read 2 more answers
A sheet of aluminum measures 55.0 cm by 23.3 cm. If the volume is 2.90 cm^3 what is the thickness of the foil?
tia_tia [17]

Answer:

0.0023 cm

Explanation:

The following data were obtained from the question:

Length (L) = 55 cm

Breadth (B) = 23.3 cm

Volume (V) = 2.9 cm³

Thickness (T) =?

Thus, we can obtain the thickness of the aluminum foil as illustrated below:

V = L × B × T

2.9 = 55 × 23.3 × T

2.9 = 1281.5 × T

Divide both side by 1281.5

T = 2.9/1281.5

T = 0.0023 cm

Therefore, the thickness of the aluminum foil is 0.0023 cm

3 0
3 years ago
URGENT HELP NEEDED! PLEASE ANSWER WITH EXPLANATION*
VladimirAG [237]

Answer:

1) 94.0° C, 2) 34.7°C

Explanation:

1)

Q=mcΔt° =mc(t2 - t1)

2350 J = 85.0 g* 0.385 J/(g*°C) *(t2 - 22.2°C)

t2 - 22.2°C = 71.81°C

t2 = 94.0° C

2)

Q=mcΔt° =mc(t2 - t1)

- 2070 J = 75.0 g * 0.903 J/(g*°C) *(t2 -65.3°C)

t2 - 65.3°C =  - 30.56°C

t2 = 34.7°C

6 0
3 years ago
A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm
Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 ^{\circ}C or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55^{\circ}C = 328 K

Initial pressure = P = 845 mmHg

Assuming final  to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg  

The final temperature is obtained by following relation at constant volume

\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}

The final temperature is 407.57 K

7 0
3 years ago
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