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elixir [45]
3 years ago
15

How many moles are in 6.99 x 1020 formula units of magnesium bromide (MgBr2)? Round your answer to 2 decimal places and, if need

ed, enter scientific notation like this 6.02e23 (would mean 6.02 x 1023.)
Chemistry
1 answer:
gogolik [260]3 years ago
6 0

Answer:

1.16x10^–3 mole

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 formula units. This implies that 1 mole of MgBr2 also contains 6.02x10^23 formula units.

Now, if 1 mole of MgBr2 contains 6.02x10^23 formula units,

Then Xmol of MgBr2 will contain 6.99x10^20 formula units i.e

Xmol of MgBr2 = 6.99x10^20/6.02x10^23

Xmol of MgBr2 = 1.16x10^–3 mole

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7 0
2 years ago
Determine the molarity of a 6.0 mole% sulfuric acid solution with SG-a 1.07 Note: Atomic Weight: S (32), O 16); H (O)
marin [14]

Answer:

The molarity of a 6.0 mole% sulfuric acid solution is 2.8157 Molar.

Explanation:

Suppose there are 100 moles in solution:

Moles of sulfuric acid = 6% of 100 moles = 6 moles

Mass of 6 moles of sulfuric acid = 6 mol × 98 g/mol=588 g

Moles of water = 100%- 6% = 94%= 94 moles

Mass of water = 94 mol × 18 g/mol = 1692 g

Specific gravity of the solution ,S.G= 1.07

Density of solution = D

S.G=\frac{D}{d_w}

d_w = density of water = 1 g/mL

D=S.G\times d_w=1.07\times 1 g/mL=1.07 g/mL

Mass of the solution = 588 g + 1692 g = 2280 g

Volume of the solution = V

Volume = \frac{Mass}{Density}

=\frac{2280 g}{1.07 g/mL}=2130.84 mL=2.13084 L

1 mL = 0.001 L

Molarity = \frac{n}{V(L)}

n = number of moles of compound

V = volume of the solution in L

here we have ,n = 6 moles of sulfuric acid

V = 2.13084 L

So, the molarity of the solution is :

Molarity=\frac{6 mol}{2.13084 L}=2.8157 mol/L

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