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elixir [45]
2 years ago
15

How many moles are in 6.99 x 1020 formula units of magnesium bromide (MgBr2)? Round your answer to 2 decimal places and, if need

ed, enter scientific notation like this 6.02e23 (would mean 6.02 x 1023.)
Chemistry
1 answer:
gogolik [260]2 years ago
6 0

Answer:

1.16x10^–3 mole

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 formula units. This implies that 1 mole of MgBr2 also contains 6.02x10^23 formula units.

Now, if 1 mole of MgBr2 contains 6.02x10^23 formula units,

Then Xmol of MgBr2 will contain 6.99x10^20 formula units i.e

Xmol of MgBr2 = 6.99x10^20/6.02x10^23

Xmol of MgBr2 = 1.16x10^–3 mole

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Adding energy has no effect on the rate of evaporation? True or False ?
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False

Explanation:

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5 0
2 years ago
In adding the measurements 11.074 m, 18.2m, and 16.943 m, what should be the number of scientific figures in the result
Artemon [7]

18.2 is the best answer

6 0
3 years ago
Aluminum metal reacts with bromine, a red-brown liquid with a noxious odor. The reaction is vigorous and produces aluminum bromi
GuDViN [60]

<u>Answer:</u> The mass of bromine reacted is 160.6 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}        .....(1)

Given mass of aluminium = 18.1 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{18.1g}{27g/mol}=0.670mol

The chemical equation for the reaction of aluminium and bromide follows:

2Al+3Br_2\rightarrow 2AlBr_3

By Stoichiometry of the reaction:

2 moles of aluminium reacts with 3 moles of bromine gas

So, 0.670 moles of aluminium will react with = \frac{3}{2}\times 0.670=1.005mol of bromine gas.

Now, calculating the mass of bromine gas, we use equation 1:

Moles of bromine gas = 1.005 moles

Molar mass of bromine gas = 159.81 g/mol

Putting values in equation 1, we get:

1.005mol=\frac{\text{Mass of bromine}}{159.81g/mol}\\\\\text{Mass of bromine}=(1.005mol\times 159.81g/mol)=160.6g

Hence, the mass of bromine reacted is 160.6 grams.

5 0
2 years ago
If 8.23 g of magnesium chloride react completely with sodium phosphate, how many grams of magnesium phosphateare produced
steposvetlana [31]

Answer:

The correct answer is 7.57 grams of magnesium phosphate.

Explanation:

Based on the given question, the chemical reaction taking place is:  

2Na₃PO₄ (aq) + 3MgCl₂ (aq) ⇒ Mg₃(PO₄)2 (s) + 6NaCl (aq)

From the given reaction, it is evident that two moles of sodium phosphate reacts with three moles of magnesium chloride to produce one mole of magnesium phosphate.  

Based on the given information, 8.23 grams of magnesium chloride reacts completely with sodium phosphate, therefore, magnesium chloride in the given case is the limiting reagent.  

In the given case, 3 moles of magnesium chloride produce 1 mole of magnesium phosphate. Therefore, 1 mole of magnesium chloride will produce 1/3 mole of magnesium phosphate.  

The molecular mass of magnesium chloride is 95.21 grams per mole. So, 1 mole of magnesium chloride is equivalent to 95.21 grams of magnesium chloride.  

On the other hand, the molecular mass of magnesium phosphate is 262.85 grams per mole. Therefore, 1 mole of magnesium phosphate is equal to 262.85 grams of magnesium phosphate.  

As seen earlier that 1 mole of magnesium chloride = 1/3 moles of magnesium phosphate. So,  

95.21 grams of magnesium chloride = 1/3 × 262.85 grams of magnesium phosphate

= 262.85 / 3 grams of magnesium phosphate

1 gram of magnesium chloride = 262.85 / 3 × 95.21 grams of magnesium phosphate

8.23 grams of magnesium chloride = 262.85 / 3 × 95.21 × 8.23 grams of magnesium phosphate

= 7.57 grams of magnesium phosphate

Hence, when 8.23 grams of magnesium chloride when reacts completely with sodium phosphate, it produces 7.57 grams of magnesium phosphate.  

8 0
2 years ago
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