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Alecsey [184]
3 years ago
5

Sodium has lost 2 electrons. What is its ion notation?

Chemistry
1 answer:
Gwar [14]3 years ago
7 0

Answer:

Na²⁺

Explanation:

lost 2 electrons, so its charge would be 2+. If it were to gain an electron, the charge would be negative.

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Did you mean "atp"? if so It is less I hope this helps please mark brainliest :)
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What is a material which cannot be broken down or changed into another substance using chemical matters?
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Elements cannot be broken down in this fashion.  

Compounds, homogeneous mixtures, and heterogeneous mixtures can be broken down or separated with chemical processes, or in some cases, just by manual separation.
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During the nuclear fission of plutonium-244, barium-144 produced, along with an unknown nucleus and three neutrons. What must be
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Answer:

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Forensic toxicology involves not only the area of toxicology, but also the use of areas such as analytic chemistry and pharmacol
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3 0
3 years ago
Read 2 more answers
A 25.0 ml sample of 0.723 m hclo4 is titrated with a 0.27303 m koh solution. the h3o+ concentration after the addition of 66.2 m
tia_tia [17]
This doesn't need an ICE chart. Both will fully dissociate in water.

Assume HClO4 and KOH reacts with one another. All you need to do is determine how much HClO4 will remain after the reaction. Calculate pH.

Step 1:

write out balanced equation for the reaction

HClO4+KOH ⇔ KClO4 + H2O

the ratio of HClO4 to KOH is going to be 1:1. Each mole of KOH we add will fully react with 1 mole of HClO4

Step 2:

Determining the number of moles present in HClO4 and KOH

Use the molar concentration and the volume for each:
25 mL of 0.723 M HClO4

Covert volume from mL into L:
25 mL * 1L/1000mL = 0.025 L

Remember:

M = moles/L so we have 0.025 L of 0.723 moles/L HClO4

Multiply the volume in L by the molar concentration to get:

0.025L x 0.723mol/L = 0.0181 moles HClO4.

Add 66.2 mL KOH with conc.=0.273M
66.2mL*1L/1000mL = .0662 L
.0662L x 0.273mol/L = 0.0181 moles KOH

Step 3:

Determine how much HClO4 remains after reacting with the KOH.

Since both reactants fully dissociate and are used in a 1:1 ratio, we just subtract the number of moles of KOH from the number of moles of HClO4:

moles HClO4 = 0.0181; moles KOH = 0.0181, so 0.0181-0.0181 = 0

This means all of the HClO4 is used up in the reaction.

If all of the acid is fully reacted with the base, the pH will be neutral = 7.

Determine the H3O+ concentration:

pH = -log[H3O+]; [H3O+] = 10-pH = 10-7

The correct answer is 1.0x10-7.
3 0
3 years ago
Read 2 more answers
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