<span>2Kg50m/
s2.5m/
s2<span>2m/
s2</span></span>
<u>Answer:</u>
Magnitude of resultant velocity of kayaker to the nearest tenth = 10 m/s
Direction of resultant velocity of kayaker = 49.32⁰ South of west.
<u>Explanation:</u>
Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.
First kayaker paddles at 4.0 m/s in a direction 30° south of west, kayaker paddles at 4.0 m/s in a direction 210° anticlockwise from positive horizontal axis.
So velocity of kayaker = 4 cos 210 i + 4 sin 210 j = -3.46 i - 2 j
He then turns and paddles at 3.7 m/s in a direction 20° west of south, kayaker paddles at 3.7 m/s in a direction 250° anticlockwise from positive horizontal axis.
So that velocity = -1.27 i - 3.48 j
So resultant velocity of kayaker = -3.46 i - 2 j +(-1.27 i - 3.48 j) = -4.71 i - 5.48 j
Magnitude of resultant velocity of kayaker = 
Magnitude of resultant velocity of kayaker to the nearest tenth = 10 m/s
Direction of resultant positive horizontal axis, θ = tan⁻¹(-5.48/-4.71) = 229.32⁰ = 49.32⁰ South of west.
Explanation:
a) We need to write down first Newton's 2nd law as applied to the given system. The equations of motion for the x- and y-axes can be written as follows:


From Eqn(2), we see that

so using Eqn(3) on Eqn(1), we get

Solving for the acceleration, we see that


b) Now that we have the acceleration, we can now solve for the velocity of the crate at the bottom of the plane. Using the equation

Since the crate started from rest,
Thus our equation reduces to



Answer:

Explanation:
From the question we are told that:
Dimension of Wall:

Electric field 
Angle 
Generally the equation for electric Flux is mathematically given by



The acceleration of the car is 0.5 meters per seconds square.
Given the following data:
- Initial velocity, U = 30 m/s
Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.
To find the acceleration of the car, we would use the third equation of motion;
Mathematically, the third equation of motion is given by the formula;

<em>Acceleration, a </em><em>=</em><em> 0.5 </em>
<em></em>
Therefore, the acceleration of the car is 0.5 meters per seconds square.
Read more: brainly.com/question/8898885