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Anit [1.1K]
3 years ago
7

A roller-coaster car moves 172 ft horizontally and then rises 115 ft at an angle of 31.0° above the horizontal. it next travels

115 ft at an angle of 48.0° downward (below the horizontal). what is its displacement from its starting point? (assume the initial horizontal motion of the car to be along the +x axis.)
Physics
1 answer:
lianna [129]3 years ago
4 0

172 + 115 cos 31 +115 cos 48 horizontally

115 sin 31 - 115 sin 48  vertically

possibly need some drawing

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<u>Answer:</u>

  Magnitude of resultant velocity of kayaker to the nearest tenth = 10 m/s

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<u>Explanation:</u>

 Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.

  First kayaker paddles at 4.0 m/s in a direction 30° south of west, kayaker paddles at 4.0 m/s in a direction 210° anticlockwise from positive horizontal axis.

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  He then turns and paddles at 3.7 m/s in a direction 20° west of south, kayaker paddles at 3.7 m/s in a direction 250° anticlockwise from positive horizontal axis.

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  So resultant velocity of kayaker = -3.46 i - 2 j +(-1.27 i - 3.48 j) = -4.71 i - 5.48 j

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y:\;\;\;\;\;N - mg\cos 25° = 0\;\;\;\;\;\;\;\;\;(2)

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mg\sin 25° - \mu_kmg\cos 25° = ma

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To find the acceleration of the car, we would use the third equation of motion;

Mathematically, the third equation of motion is given by the formula;

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Read more: brainly.com/question/8898885

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