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user100 [1]
3 years ago
10

Two 2.0 kg masses are 1.1 m apart (center to center) on a frictionless table. Each has + 9.6 μC of charge. PART A

Physics
1 answer:
mario62 [17]3 years ago
5 0

Answer:

A) Force = 0.69 N

B) Acceleration = 0.34 m/s^2

Explanation:

The electric force is given by the expression:

F_e= K *\frac{q_1*q_2}{r^2}

K is the Coulomb constant equal to 9*10^9 N*m^2/C^2, q1 and 12 is the charge of the particles, and r is the distance:

F_e = 9*10^9 Nm^2/C^2 * \frac{(9.6*10^{-6}C)^2}{(1.1m)^2} = 0.69 N

Part B.

For the acceleration, you need Newton's second Law:

F = m*a

Then,

a = \frac{F}{m} = \frac{0.69 N}{2 kg} = 0.34 m/s^2

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The mass of this bag of cement in S.I. units (kg) is equal to 0.062 kilograms.

<u>Given the following data:</u>

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To calculate the mass of this bag of cement in S.I. units (kg):

<h3>How to convert to S.I. units.</h3>

In Science, kilograms (kg) is the standard unit of measurement or S.I. units of the mass of a physical object. Thus, we would convert the value of the mass of this bag of cement in grams to kilograms (kg) as follows:

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