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Scrat [10]
2 years ago
8

What is the acceleration of a 5 kg mass pushed by a 10 n force?

Physics
2 answers:
pav-90 [236]2 years ago
6 0
<span>2Kg50m/
s2.5m/
s2<span>2m/
s2</span></span>
lorasvet [3.4K]2 years ago
3 0
∑F=ma, newton's second law. m=5kg, ∑F= 10N, solve for a. 10N/5kg= 2m/s^2. 
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What is light intensity? ​
soldi70 [24.7K]

Light intensity is the "amount of light given off a light source." Also, is the measure the wavelength of the amount of light given off by a light source.

Hope this helps.

7 0
2 years ago
Read 2 more answers
Energy is to be stored in a flywheel in the shape of a uniform solid disk with a radius of R = 1.22 m and a mass of 67.0 kg . To
eduard

Answer: 71.7 KJ

Explanation:

The rotational kinetic energy of a rotating body can be written as follows:

Krot = ½ I ω2

Now, any point on the rim of the flywheel, is acted by a centripetal force, according to Newton’s 2nd Law, as follows:

Fc = m. ac

It can be showed that the centripetal acceleration, is related with the angular velocity and the radius, as follows:

ac =  ω2 r

We know that this acceleration has a limit value, so , we can take this limit to obtain a maximum value for the angular velocity also.

As the flywheel is a solid disk, the rotational inertia I is just ½ m r2.

Replacing in the expression for the Krot, we have:

Krot= ½ (1/2 mr2.ac/r) = ¼ mr ac = ¼ 67.0 Kg. 1.22 m . 3,510 m/s2 = 71. 7 KJ

5 0
2 years ago
Which is an example of a scientist using a conceptual model to describe a volcano?
Yuri [45]
I would say D would be the answer. but is this even a real like homework question 

8 0
3 years ago
Read 2 more answers
Which equation correctly relates mechanical energy, thermal energy and total of energy when there is friction present in the sys
agasfer [191]

Answer:

E total = ME + E thermal

Explanation:

APEX

4 0
3 years ago
While walking past a construction site, a person notices a pipe sticking out of a second floor window with water pouring out. As
tia_tia [17]

Answer:

Its diameter increases as it flows down from the pipe. Assuming laminar flow for the water, then Bernoulli's equation can be applied.

P1-P2 + (rho)g(h1 - h2) + 1/2(rho)(v1² - v2²) = 0

Explanation:

P1 = P2 = atmospheric pressure so, P1 - P2 = 0

h1 is greater than h2 so h1-h2 is positive. Rearranging the equation above 2{ (rho)g(h1-h2) + 1/2(rho)v1²}/rho = v2²

From the continuity equation for fluids

A1v1 = A2v2

v2 = A1v1/A2

Substituting into the equation above

(A1v1/A2)² = 2{ (rho)g(h1-h2) + 1/2(rho)v1²}/rho

Making A2² the subject of the formula,

A2² = (A1v1)²× rho/(2{ (rho)g(h1-h2) + 1/2(rho)v1²}

The denominator will be greater than the numerator and as a result the diameter of the flowing stream decreases.

Thank you for reading.

4 0
2 years ago
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