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lutik1710 [3]
3 years ago
8

A circle with circumfrence 10, has an arc with 160 degree angle

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0
Soo what is the question is there more to this
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<span>1/8 , ...... , 1/4

1/8 = 2/16
1/4 = 4/16

2/16 , 3/16 , 4/16

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</span>
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To find the number of centimeters in 10 inches, multiply the number of inches given (10) by _____.
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Helpppp ASAP<br> Drag Values To complete each equation
dimulka [17.4K]

Given:

Part A: \frac{\left(17^{3}\right)^{6} \cdot 17^{-10}}{17^{8}}

Part B: \left(17^{6}\right)^{3} \cdot 17^{-9}

To find:

The value of each expression.

Solution:

Part A:

Using exponent rule: (a^m)^n=a^{mn}

$\frac{\left(17^{3}\right)^{6} \cdot 17^{-10}}{17^{8}}=\frac{\left(17\right)^{3\times   6} \cdot 17^{-10}}{17^{8}}

                      $=\frac{(17)^{18} \cdot 17^{-10}}{17^{8}}

Using exponent rule: a^m \cdot a^{n}= a^{m+n}

                      $=\frac{(17)^{18+(-10)}}{17^{8}}

                      $=\frac{17^{8}}{17^{8}}

Cancel the common factor, we get

                      = 1

$\frac{\left(17^{3}\right)^{6} \cdot 17^{-10}}{17^{8}}=1

Part B:

\left(17^{6}\right)^{3} \cdot 17^{-9}

Using exponent rule: (a^m)^n=a^{mn}

\left(17^{6}\right)^{3} \cdot 17^{-9}=\left(17\right)^{6\times 3} \cdot 17^{-9}

                   =(17)^{18} \cdot 17^{-9}

Using exponent rule: a^m \cdot a^{n}= a^{m+n}

                   =(17)^{18+(-9)}

                   =17^9

\left(17^{6}\right)^{3} \cdot 17^{-9}=17^9

6 0
3 years ago
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